NCr*P^r*q^(n-r)
7C4*. 75^4*. 25^(7-4)
35*. 75⁴*. 25³
35*. 316*. 016
11.06*. 016
. 1769
=. 177
Answer:
fg(x) = √143x+121
Step-by-step explanation:
in such function we go right to left
given = f(x) = √11x and g(x) = 13x + 11
fg(x) =
f( 13x + 11 )
√11( 13x + 11 )
√143x+121
therefore found fg(x) = √143x+121
Answer:
See Explanation!
Step-by-step explanation:
When multiplying fractions, you do not need a common denominator, and the entire fraction gets multiplied across, however when adding or subtracting fractions, you must have a common denominator, and then only compute the numerator, as the bases are already the same
Answer:
0.8413 = 84.13% probability of a bulb lasting for at most 605 hours.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation , the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The standard deviation of the lifetime is 15 hours and the mean lifetime of a bulb is 590 hours.
This means that
Find the probability of a bulb lasting for at most 605 hours.
This is the pvalue of Z when X = 605. So
has a pvalue of 0.8413
0.8413 = 84.13% probability of a bulb lasting for at most 605 hours.
17,158/52= 329.96 rounded to the nearest tenth is 330