3 years ago

PLEAAASSSSEEEEE HELP ME WITH THIS I REALLY NEED HELP PLEASE PUT THE CORRECT ANSWER

Mathematics

1 answer:

Alisiya [41]3 years ago

7 0

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kirill115 [55]

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3 years ago

Find the ninth term of the sequence sqrt 5, sqrt 10, ^2sqrt 5

hjlf

The rule of geometric sequence is ⇒⇒⇒ a * r^(n-1)
Where a is the first term and r is the common ratio
for the given sequence √5 , √10 , 2√5 , .......
a = √5
r = √10 / √5 = √2
The ninth term = √5 * (√2)^(9-1) = √5 * (√2)⁸ = 16 √5

the correct answer is the third option 16√5

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3 years ago

Y=6x/5 +27 find y-intercept and slope

mixas84 [53]

Answer:

General equation of a line is given by y = mx +c, where m is the gradient /slope, c is the intercept. To find for the intercept on y- axis, put x = 0.
$y = \frac{6(0)}{5 } + 27 \\ y = \frac{0}{5} + 27 \\ y = 27 \\ therefore \: the \: intercept \: on \: y \: is \: 27 \\$
By comparison,
$y = mx + \: c \\ y = \frac{6}{5} x \: +27 \\ m = \frac{6}{5 \: } \: \\ hence \: slope \: is \: \frac{6}{5}$