The standard form of a circle is
![(x-h) ^{2} +(y-k) ^{2} = r^{2}](https://tex.z-dn.net/?f=%28x-h%29%20%5E%7B2%7D%20%2B%28y-k%29%20%5E%7B2%7D%20%3D%20r%5E%7B2%7D%20)
where h and k are the center and x and y are the coordinates you're given. We need to solve for the radius to finish this off correctly. Filling in, we have
![(5-0) ^{2} +(-4-0) ^{2} = r^{2}](https://tex.z-dn.net/?f=%285-0%29%20%5E%7B2%7D%20%2B%28-4-0%29%20%5E%7B2%7D%20%3D%20r%5E%7B2%7D%20)
and
![25+16= r^{2}](https://tex.z-dn.net/?f=25%2B16%3D%20r%5E%7B2%7D%20)
, giving us that
![r^{2}=41](https://tex.z-dn.net/?f=%20r%5E%7B2%7D%3D41%20)
. Therefore, our equation is
Answer:
B. 21
Step-by-step explanation:
<em>Given, 9−7x=5−3x</em>
<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.</em>
<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.⇒9−5=7x−3x</em>
<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.⇒9−5=7x−3x⇒4=4x</em>
<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.⇒9−5=7x−3x⇒4=4x⇒x= </em><em>4</em><em>/</em><em>4</em><em> </em><em> =1</em>
<em> =1Hence, required solution is x=1.</em>
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Answer:
the answer for the question is 10+x
y-3
Answer:
how you would keep your math teacher focused
Step-by-step explanation:
try sending your teacher reminder emails, or put some sticky notes on their desk