Pls help i need this question by 8:00am tomorrow
2 answers:
You might be interested in
Answer x=5, y= 3.5
Find y by plugging the x value into the 2nd equation
4(2y-2) -9=11
8y - 8 - 9 =11 combine like terms
8y = 28 divide both sides by 8
y = 3.5
Now find x
Plug your y value into first equation
X = 2(3.5) -2
X= 7-2
X=5
You can check your work by putting your x or y values into the equations
For the first equation
5=2(3.5) -2
5=5
For the second equation
4(5) -9 = 11
20 - 9 = 11
11 =11
Find y by plugging the x value into the 2nd equation
4(2y-2) -9=11
8y - 8 - 9 =11 combine like terms
8y = 28 divide both sides by 8
y = 3.5
Now find x
Plug your y value into first equation
X = 2(3.5) -2
X= 7-2
X=5
You can check your work by putting your x or y values into the equations
For the first equation
5=2(3.5) -2
5=5
For the second equation
4(5) -9 = 11
20 - 9 = 11
11 =11
Answer:
0.375
Step-by-step explanation:
Given that F is the event that a student is enrolled in a finance course, and let S be the event that a student is enrolled in a statistics course.
It is known that 40% of all students are enrolled in a finance course and 35% of all students are enrolled in statistics. Included in these numbers are 15% who are enrolled in both statistics and finance.
P(F) = 0.40: P(S) = 0.35: P(FS) = 0.15
A student is randomly selected, and it is found that the student is enrolled in finance.
Probability that this student is also enrolled in statistics/ student is enrolled in finance.
=
(Using conditional probability formula)