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stiv31 [10]
2 years ago
6

In 2010, there were about 246 million vehicles (cars and trucks) and about 308.7 million people in the United States.1 The numbe

r of vehicles grew 15.5⁢ % over the previous decade, while the population has been growing at 9.7⁢ % per decade. If the growth rates remain constant, when will there be, on average, one vehicle per person?
Mathematics
1 answer:
belka [17]2 years ago
5 0

Answer:

2054

Step-by-step explanation:

The equation for the growth of people = 308.7(1097)^x

The equation for the growth of vehicles = 246(1155)^x

If the number of both are equal tham

308.7(1097)^x=246(1155)^x

Dividing both sides by 246

1.254878(1097)^x=(1155)^x

Dividing both sides by (1097)^x

1.254878=(1155÷1097)^x

X=4.406 decades

X=44 years

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harina [27]
Well 42 divided by 2 is 21. than to double check you can do 21 plus 21 equals 42.
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TVs are described by the length of their diagonals. The diagonal of a TV is
elena55 [62]

Answer:

32

Step-by-step explanation:

4 0
2 years ago
Help, please the question and thank you
Law Incorporation [45]

Answer:

The scale factor is 1.5.

Step-by-step explanation:

Divide the length of the image, 12, by the length of the preimage, 8, which will give you 1.5

12 ÷ 8 = 1.5

Therefore, the scale factor of the image is 1.5.

3 0
2 years ago
$43,800 at 4.8% for 2 years
Mashutka [201]
It would be: P * R * T /100
= 43800 * 4.8 * 2 /100
= 420480 / 100
= 4204.80

So, your final answer is $4204.80

Hope this helps!
4 0
2 years ago
Read 2 more answers
If possible could you explain how to get the answer if not it is ok.
Softa [21]

Rules of exponents come in hand here.

Multiplication rule: a^m x a^n = a^ m+n

Division rule: a^m / a^n = a^m-n

Negative exponent: a^-m = 1/a^m; 1a^-m =a^m

So it would be (-3)^7+5 / (-3)^-2; (-3)^12 / (-3)^-2; (-3)^12 x (-3)^2; (-3)^14

The answer is (-3)^14. If you multiply it out it is 4,782,969.

3 0
3 years ago
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