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enot [183]
3 years ago
9

HELPPPPPPPP 7TH GRADE MATH

Mathematics
1 answer:
My name is Ann [436]3 years ago
8 0

Answer:

D. 1 x 9 x 4

Step-by-step explanation:

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Lim x tends to π÷2 , then what is the value of (tanx + cotx) ÷ ( tanx - cotx)​
KiRa [710]

(tan(<em>x</em>) + cot(<em>x</em>)) / (tan(<em>x</em>) - cot(<em>x</em>)) = (tan²(<em>x</em>) + 1) / (tan²(<em>x</em>) - 1)

… = (sin²(<em>x</em>) + cos²(<em>x</em>)) / (sin²(<em>x</em>) - cos²(<em>x</em>))

… = -1/cos(2<em>x</em>)

Then as <em>x</em> approaches <em>π</em>/2, the limit is -1/cos(2•<em>π</em>/2) = -sec(<em>π</em>) = 1.

8 0
2 years ago
Please help me! Whoever gets the correct answer and explains it will get marked Brainliest!!
Helen [10]

1. The answer is 0.425

2. the answer is 0.425

3. the answer is 0.2125

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3 years ago
What is the the volume of this?<br><br> Also you can explain just make the explanation short
fgiga [73]
15×20×10=3000
10×20×15=3000
3000+3000=6000 cm^{2}

6 0
3 years ago
PLEASE HELP FAST!!!
Llana [10]

Answer:

4500 miles

Step-by-step explanation:

750 rounded to the nearest hundred is 800. 2,488 rounded to the nearest hundred is 2,500. 155 rounded to the nearest hundred is 200. 1,015 rounded to the nearest hundred is 1,000. So 800+2,500+200+1,000= 4,500

8 0
3 years ago
The pressure applied to a leverage bar varies inversely as the distance from the object. If 150 pounds is required for a distanc
AlexFokin [52]

Answer:

500 pounds

Step-by-step explanation:

Let the pressure applied to the leverage bar be represented by p

Let the distance from the object be represented by d.

The pressure applied to a leverage bar varies inversely as the distance from the object.

Written mathematically, we have:

p \propto \dfrac{1}{d}

Introducing the constant of proportionality

p = \dfrac{k}{d}

If 150 pounds is required for a distance of 10 inches from the object

  • p=150 pounds
  • d=10 inches

150 = \dfrac{k}{10}\\\\k=1500

Therefore, the relationship between p and d is:

p = \dfrac{1500}{d}

When d=3 Inches

p = \dfrac{1500}{3}\\\implies p=500$ pounds

The pressure applied when the distance is 3 inches is 500 pounds.

4 0
3 years ago
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