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Paraphin [41]
3 years ago
7

terri planned a fence for her pool.she asked bess fences to fence the largest area possible using 40 feet of fencing. what was t

he area?
Mathematics
1 answer:
Elza [17]3 years ago
4 0
There could be many answers to that problem, the most obvious being 5 by 8
another could be 10 by 4. hope that helped ;) 
You might be interested in
1. La suma de dos números es 115. El número mayor es dos veces más 22 unidades que el otro. Hallar
Lerok [7]

De acuerdo con un sistema de ecuaciones, tiene-se que los números son 31 y 84.

----------------

  • En el sistema de ecuaciones, tiene-se que los números son x e y.
  • Suma de 115, o sea, x + y = 115
  • <u>El número mayor es dos veces más 22 unidades que el otro</u>, o sea, x = 2y + 22

----------------

Primero se encuenta el número menor, <u>reemplazando la segunda ecuación en la primera:</u>

x + y = 115

2y + 22 + y = 115

3y = 93

y = \frac{93}{3}

y = 31

----------------

El número mayor es dado en <u>función de el menor</u>, o sea:

x = 2y + 22 = 2(31) + 22 = 62 + 22 = 84

Los números son 31 y 84.

Otro problema resuelto por sistema de ecuaciones es dado en brainly.com/question/24637096

6 0
2 years ago
Sums of a sequence: How many total gifts did my true love give to me during the entire 12 days of Christmas? Hint: Without any o
ale4655 [162]
<span> On the first day of Christmas,
my true love sent to me
A partridge in a pear tree. On the second day of Christmas,
my true love sent to me
Two turtle doves,
And a partridge in a pear tree. On the third day of Christmas,
my true love sent to me
Three French hens,
Two turtle doves,
And a partridge in a pear tree. </span>

The song continues, adding 4 calling birds on the 4th day, 5 golden rings on the 5th, and so on up to the 12th day, when 12 drummers add to the cacophony of assorted birds, pipers and lords leaping all over the place.

Notice that on each day there is one partridge (so I will have 12 partridges by the 12th day), and each day from the second day onwards there are 2 doves (so I will have 22 doves), and from the 3rd there are 3 hens (total of 30 hens), and so on.

So, how many presents are there altogether?

Partridges: 1 × 12 = 12

Doves: 2 × 11 = 22

Hens 3 × 10 = 30

Calling birds: 4 × 9 = 36

Golden rings: 5 × 8 = 40

Geese: 6 × 7 = 42

Swans: 7 × 6 = 42

Maids: 8 × 5 = 40

Ladies: 9 × 4 = 36

Lords: 10 × 3 = 30

Pipers: 11 × 2 = 22

Drummers: 12 × 1 = 12

Total = 364

We observe that we have the same number of partridges as drummers (12 of each); doves and pipers (22 of each); hens and lords (30 of each) and so on. So the easiest way to count our presents is to add up to the middle of the list and then double the result: (12 + 22 + 30 + 36 + 40 + 42) × 2 = 364.


3 0
3 years ago
Read 2 more answers
Is this right I am positive but I need to pass this test
FrozenT [24]

Answer:

It's not a polygon

Step-by-step explanation:

Polygons are always 2D. This shape is 3D. Everything else is fine.

Please mark as Brainliest! :)

Have a nice day.

3 0
2 years ago
Use the discriminant to determine the number of real solutions to the equation,<br> 10n^2 = 10 - 8n
galben [10]

Answer:

2 real solutions

Step-by-step explanation:

Get all the terms to one side

10n^2 = 10 - 8n

10n^2 +8n -10 =0

ax^2 +bx+c =0

The discriminant is

b^2 -4ac

8^2 - 4(10)(-10)

64 +400

464

If the discriminant is greater than 0 we have 2 real solutions

6 0
2 years ago
Write an algebraic expression for “5 times the sum of a number and 3”
Firdavs [7]

Answer:

5(x+3)

Step-by-step explanation:

:)

3 0
3 years ago
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