Answer:
66.42degrees
Step-by-step explanation:

 
        
                    
             
        
        
        
The answer to this answer is B
        
                    
             
        
        
        
 <span>lim (x → π/2) (sinx)^(tanx) 
= lim (x → π/2) e^[(tanx) ln (sinx)] 
= e^ [lim (x → π/2) (tanx) ln (sinx)] ... (1) 
lim (x → π/2) (tanx) ln (sinx) 
= lim (x → π/2) [ln(sinx) / cotx] 
Using L'Hospital'stheorem, 
= lim (x → π/2) [- cotx / cosec^2 x] 
= 0 
Plugging in ( 1 ), 
required limit = e^0 = 1 
=>Answer is 1.
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