To which graph does the point (−1, 4) belong?

Mathematics

2 answers:

Verdich [7]3 years ago

6 0

Insert x = -1 and y = 4 into the first inequality:-
4 <= -(-1) + 4 = 5

so this fits

Its A

marta [7]3 years ago

4 0

Answer: First one

Step-by-step explanation:

Due to slope form which is y=mx + b.

-1 = x and y = 4.

It does not show the one because it would be equal to X, but it does show the negative

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Quadrilateral ABCD is inscribed in a circle. Find the measure of each of the angles of the quadrilateral. Show your work.

LuckyWell [14K]

Step-by-step explanation:

Quadrilateral ABCD is inscribed in a circle.

Opposite angles of a Quadrilateral are Supplementary.

$\therefore \: \angle A + \angle C = 180° \\ \therefore \:(2x + 3) \degree+ (2x + 1) \degree = 180° \\ \therefore \: (4x + 4) \degree = 180° \\ \therefore \: (4x + 4) = 180 \\ \therefore \: 4x = 180 - 4 \\ \therefore \: 4x = 176 \\ \therefore \: x = \frac{176}{4} \\ \therefore \: x = 44 \\ \\ m\angle A = (2x + 3) \degree \\ = (2 \times 44 + 3) \degree \\ = (88 + 3) \degree \\ \huge \red{ \boxed{ \therefore \: m\angle A =91 \degree}} \\ \\ m\angle C = (2x + 1) \degree \\ = (2 \times 44 + 1) \degree \\ = (88 + 1) \degree \\ \huge \red{ \boxed{ \therefore \: m\angle C=89\degree}} \\ \\ m\angle D= (x - 10) \degree \\ = (44 - 10) \degree \\ \huge \red{ \boxed{ \therefore \: m\angle D =34\degree}} \\ \\ similarly \\ \\ \huge \red{ \boxed{ \therefore \: m\angle B = 146\degree}} \\ \\$

6 0

2 years ago

Bob has two weekend jobs last weekend he made a total of $77 after working as a cashier for 5 hours and delivering newspapers fo

OlgaM077 [116]

Answer: $9 per hour at his job as a cashier and $8 per hour at his job delivering newspapers.

Step-by-step explanation:

1. Let's call the amount he got paid per hour at his job as a cashier: $x$ .

Let's call the amount he got paid per hour at his job delivering newspapers: $y$ .

2. Keeping on mind the information given in the problem above, you can make the following system of equations:

$\left \{ {{5x+4y=77 \atop {6x+3y=78}} \right.$

3. You can solve it by applying the Substitution method, as following:

- Solve for one of the variables from one of the equations and substitute it into the other equation to solve for the other variable and calculate its value.

- Substitute the value obtained into one of the original equations to solve for the other variable and calculate its value.

4. Therefore, you have:

$5x+4y=77\\5x=77-4y\\x=\frac{77-4y}{5}=15.4-0.8y$