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2 years ago

8

Which of the following is a validation of concurrency between two polygons?

1 answer:

tatiyna2 years ago

3 0

Concurrent validity is a type of evidence that can be gathered to defend the use of a test for predicting other outcomes. It is a parameter used in sociology, psychology, and other psychometric or behavioral sciences. Concurrent validity is demonstrated when a test correlates well with a measure that has previously been validated. The two measures may be for the same construct, but more often used for different, but presumably related, constructs.

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At a particular restaurant each mozzarella stick has 90 cal in each pizza roll has 80 cal. A combination meal with the mozzarell

serious [3.7K]

Answer:

The meal consist 11 mozzarella sticks and 6 pizza rolls.

Step-by-step explanation:

We are given the following in the question:

Calories in mozzarella stick = 90

Calories in pizza roll = 80

Let x be the number of a mozzarella stick and y be the number of pizza rolls.

Total calories in meal = 1470

Thus, we can write the equation:

$90x + 80y = 1470$

There are five more mozzarella sticks than pizza roll.

Thus, we can write the equation:

$x = y + 5\\x-y = 5$

Solving the two equations, we get,

$90x+80y+80x-80y = 1470 + 400\\170x = 1870\\x = 11\\y = 11-5 = 6$

Thus, the meal consist 11 mozzarella sticks and 6 pizza rolls.

4 0

2 years ago

Please help me I am confused

nadezda [96]

Answer: X= 11

Step-by-step explanation:

3 0

2 years ago

Y^1/3(y^4/9-8y^2/9) how do you solve this

Step2247 [10]

I hope this helps you

5 0

3 years ago

For the members of a neighborhood meeting group, the probability of randomly selecting a member who likes to cook is 42%, the pr

Monica [59]

Answer: Probability of randomly selecting a member who likes to cook or likes to sew = 58%

Step-by-step explanation:

Since we have given that

Probability of a randomly selecting a member who likes to cook=P(C) = 42%

Probability of a randomly selecting a member who likes to sew =P(S)= 23%

Probability of a randomly selecting a member who likes to both cook and sew

$P(C\cap S)=7\%$

As we know the "Probability rules " :

$P(C\cup S)=P(C)+P(S)-P(S\cap C)\\\\P(C\cup S)=42+23-7\\\\P(C\cup S)=58$

So, Probability of randomly selecting a member who likes to cook or likes to sew = 58%

5 0

3 years ago

Jessica just put 14.41 gallons of fuel into her car. There were 3.6 gallons in the car to begin with. How much fuel is in jessic

SIZIF [17.4K]

Answer:

18.01 gallons

Step-by-step explanation:

14.41

3.6

=18.01

8 0

2 years ago