Let the dimensions be x and y
Given that the area is 40m²
xy = 40 ----------------- (1)
Given that the perimeter is 26
2(x + y) = 26
x + y = 13
x = 13 - y ---------------- Sub into (1)
(13 - y)y = 40
13y - y² = 40
y² - 13y + 40 = 0
(y - 8)(y - 5) = =
y = 8 or y = 5
The dimensions are 8 meters and 5 meters
I would say 465 since they go back and forth twice which is 155 x 3
9514 1404 393
Answer:
140, 35, 260/35, 7.43, 8
Step-by-step explanation:
The last section is just a summary of the preceding sections, a short description of the problem and how you worked it.
She sells the jackets for 140% of $25, or $35. 260/35 = 7.43 She can only sell a whole number of jackets, so she needs to sell 8.
Answer:
2
Step-by-step explanation:
132+10+2=144
Given:
m∠B = 44°
Let's find the following measures:
m∠A, m∠BCD, m∠CDE
We have:
• m∠A:
Angle A and Angle B are interior angles on same side of a transversal.
The interior angles are supplementary.
Supplementary angles sum up to 180 degrees
Therefore, we have:
m∠A + m∠B = 180
m∠A + 44 = 180
Subtract 44 from both sides:
m∠A + 44 - 44 = 180 - 44
m∠A = 136°
• m,∠,BCD:
m∠BCD = m∠A
Thus, we have:
m∠BCD = 136°
• m∠CDE:
Angle C and angle CDE form a linear pair.
Linear pair of angles are supplementary and supplementary angle sum up to 180 degrees.
Thus, we have:
m∠D = m∠B
m∠D = 44°
m∠CDE + m∠D = 180
m∠CDE + 44 = 180
Subract 44 from both sides:
m∠CDE + 44 - 44 = 180 - 44
m∠CDE = 136°
ANSWER:
• m∠A = 136°
,
•
,
• m∠BCD = 136°
,
•
,
• m∠CDE = 136°
