All categories

3 years ago

Factor completely. 3h^4+24h^3+21h^2. BRAINLIST PLEASE HELP FAST!!!

Mathematics

1 answer:

mote1985 [20]3 years ago

3 0

3h2 • (h + 7) • (h + 1) is the simplified version.

You might be interested in

Would a teaspoon be a good way to measure the capacity of a milk carton

Natali [406]

No, a teaspoon is too small to measure the capacity of a milk carton. You would use a quart to measure the capacity of a gallon.

Hope this helps :)

7 0

3 years ago

Read 2 more answers

3 tenths + 4 Tenths = __0.7____ tenths

vovangra [49]

Answer:

7 tenths

Step-by-step explanation:

3 tenths + 4 tenths = 3/10 + 4/10 = 0.3 + 0.4 = 0.7

= 7 tenths

6 0

3 years ago

Two trains leave two different stations 300 km apart; the first starts at noon and the second at 12 15 h. Travelling on parallel

alexgriva [62]

Answer:

See below

Step-by-step explanation:

From noon to 1500 is three hours

train A then travels 3x where x = speed in km/hr

train B only travels for 2.45 hours and covers

2.45 ( x + 15) where x + 15 is its speed in km/hr

these two values sum to the 300 km distance

3x + 2.45 ( x + 15) = 300

3x + 2.45 x + 36.75 = 300

x = 48.3 km/hr x+15= 63.3 km / hr

8 0

2 years ago

A turtle can walk 1/12 of a kilometer in an hour. The turtle is 1/5 o a kilometer away from a pond. At this speed,how long will

eimsori [14]

Answer:

It will take 5/12 hours.

Step-by-step explanation:

Given,

The speed of turtle = $\frac{1}{12}$ km per hour,

Distance covered = $\frac{1}{5}$ km,

Since,

$Speed =\frac{Distance}{Time}$

$\implies Time =\frac{Distance}{Speed}$

Hence, the speed of turtle = $\frac{\text{1}{12}}{\frac{1}{5}}$

$=\frac{5}{12}$ hour.

7 0

3 years ago

A manager at a local company asked his employees how many times they had given blood in the last year. The results of the survey

Lubov Fominskaja [6]

Answer:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

Step-by-step explanation:

For this case we have the following distribution given:

X 0 1 2 3 4 5 6

P(X) 0.3 0.25 0.2 0.12 0.07 0.04 0.02

For this case we need to find first the expected value given by:

$E(X) = \sum_{i=1}^n X_i P(X_I)$

And replacing we got:

$E(X)= 0*0.3 +1*0.25 +2*0.2 +3*0.12 +4*0.07+ 5*0.04 +6*0.02=1.61$

Now we can find the second moment given by:

$E(X^2) =\sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2)= 0^2*0.3 +1^2*0.25 +2^2*0.2 +3^2*0.12 +4^2*0.07+ 5^2*0.04 +6^2*0.02=4.97$

And the variance would be given by:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

8 0

3 years ago