If AB=9 and A lies at 5 where could B be located
2 answers:
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Answer:
Solution of the system of equations: (1, 1)
x = 1, y = 1
Explanation:
Given the below system of equations;
Note that the slope-intercept form of the equation of a line is given as;
where m = slope of the line
b = y-intercept of the line
Comparing the given system of equations with the slope-intercept equation, we can see that, for the 1st equation (y = -3x + 4), the slope(m) = -3 and y-intercept(b) = 4 and for the 2nd equation, slope(m) = 3 and y-intercept(b) = -2.
Knowing the above information, let's go ahead and graph the system of equations;
From the above graph, the point of intersection of the two lines (1, 1) is the solution of the system of equation.
Solution :
Let us consider the squares be
If x ranges from the 0 to 16 and the y ranges from 16 to 32, we see that the boundary of the region which goes from the
.
And so it is easier to find the area of region where . This is the triangle with points
as its vertices.
The area if the triangle is =
=
Now the entire area is = 256
Then,
or
Thus the answer is