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vazorg [7]
3 years ago
14

Point H is the incenter of triangle ABC. Find angle HAC.

Mathematics
2 answers:
OleMash [197]3 years ago
5 0
The answer will be D.
Rashid [163]3 years ago
4 0
Let angle HAC = A, then
cos A = 24/25 = 0.96
A = cos^-1(0.96) = 16.26
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Rob who has 13 girls phone number that are in his homeroom has 3 more than half the number that jay has what is the algebraic eq
Vikki [24]
Well Jay has 20 phone numbers. 
20j=13r-3x2 im not sure but i hope that helped a little.
8 0
3 years ago
which of the following expresses the coordinates of the foci of the conic section shown below? (x-2)^2/4+(y+5)^2/9
elena55 [62]

Step-by-step explanation:

\frac{(x - 2) {}^{2} }{4}  +  \frac{(y + 5) {}^{2} }{9}  = 1

This is the equation of the ellipse. Since the denominator is greater for the y values, we have a vertical ellipse. Remember a>b, so a

The formula for the foci of the vertical ellipse is

(h,k+c) and (h,k-c).

where c is

Our center (h,k) is (2, -5)

{c}^{2}  =  {a}^{2}  -  {b}^{2}

Here a^2 is 9, b^2 is 4.

{c}^{2}  = 9 - 4

{c}^{2}  = 5

c =  \sqrt{5}

So our foci is

(2, - 5 +  \sqrt{5} )

and

(2, - 5 -  \sqrt{5} )

6 0
2 years ago
Find the distance between the points (3,0) and (-1,-5)
nadya68 [22]

Answer:

6.4

Step-by-step explanation:

distance formula \sqrt{(x2-x1)^2+(y2-y1)^2}

\sqrt{(-1-3)^2+(-5-0)^2}

\sqrt{(-4)^2+(-5)^2}

\sqrt{16+25}

\sqrt{41}≈6.403.......

ik it doesnt make any sinse but hope this helps

7 0
3 years ago
2 times the difference between 49.5 and 37.5
Xelga [282]
I belive the answer would be....
49.5-37.5=12
2•12=24
6 0
3 years ago
Read 2 more answers
Find the volume of the triangular prism <br><br>​
andrew-mc [135]

Answer:

32inch³

Step-by-step explanation:

formula= ½bh²

½×4×4×4

½×64

= 64/2

=32inches³

7 0
2 years ago
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