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2 years ago

What is the value of the expression?

Mathematics

1 answer:

nadya68 [22]2 years ago

8 0

B use the app Photomath it helps you with this kinda questions

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Emma has saved £1.35 in 5p coins. How many 5p coins does Emma have?

valentinak56 [21]

To make calculation easier, we first multiply
1.35 × 100 = 135

then we need to find how many groups of 5 are there in 135.
to do so, we simply take
135 ÷ 5 = 27

therefore, the answer is 27.

8 0

3 years ago

You are saving up money to buy a new ipad. You begin with $25, and are able to save $40 each month. Write an

yawa3891 [41]

Answer:

567

Step-by-step explanation:

4 0

3 years ago

What is the slope of the points (-2,7) and (2,-5)? 4 -3 -12 3

Dafna1 [17]

Answer:

-3

Step-by-step explanation:

Slope is equal to (-5-7)/(2-(-2)=-12/4=-3

6 0

2 years ago

Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they

Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

$n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276$

Number of ways of choosing 3 students From all males

$n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220$

The probability that all are male of choosing '3' students

$P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }$

$P(E) = \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}$

P(E) = 0.067 = 6.71%

Final answer:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

3 0

3 years ago

John haf 99 more stickers than Sally. Sally then gave John 36 more stickers. How many more stickers would John have than Sally i

densk [106]

Hi,

John haves 99 stickers. If Sally gave him 36 more that means john haves 99 + 36 = 135 more stickers than Sally.

Hope this helps.
r3t40

5 0

3 years ago