All categories

3 years ago

Which number between 41 and 50 has more than 5 factors and is a multiply of 1

Mathematics

2 answers:

SashulF [63]3 years ago

6 0

45 i do believe is the answer

Xelga [282]3 years ago

6 0

44: 1,2,4,22,44
This is the correct answer

You might be interested in

HELP ME PLEASE IF YOU WANT :(

ella [17]

Answer:

309,000,000

Hope this helps!

3 0

3 years ago

Read 2 more answers

What is the answer? I find this very confusing for me.

vichka [17]

Answer:

Step-by-step explanation:

If you want to find the answer of the equation, sub the given information into it:

z + xz + y

we know that:

x = 5

y = 1

z = 3

We got:

= 3 + 5*3 + 1

= 3 + 15 + 1

= 19

Hope this helped :3

5 0

3 years ago

While visiting a memorial, a person approximated the angle of elevation to the top of the memorial to be 35º. After walking 255

Alenkasestr [34]

Draw a diagram to illustrate the problem as shown in the figure below.

Let h the height of the hill. =

At position A, the angle of elevation is 40°, and the horizontal distance to the foot of the hill is x.

By definition,

tan(40°) = h/x h = x tan40 = 0.8391x

(1)

At position B, Joe is (x - 450) ft from the foot of the hill. His angle of elevation is

40 + 18 = 58°.

By definition, tan(58°) = h/(x - 450)

h = (x - 450) tan(58°) = 1.6003(x-450)

h = 1.6003x - 720.135 (2)

Equate (1) and (2).

1.6003x - 720.135 = 0.8391x 0.7612x = 720.135

x = 946.0523

From (1), obtain

h = 0.8391*946.0523 = 793.8 ft

Answer: The height of the hill is approximately 794 ft (nearest integer)

6 0

2 years ago

What is 56 1/4% as a fraction in simplest form

Sever21 [200]

56.3 is your answer in simplest from

8 0

3 years ago

VEEL

Andre45 [30]

Answer:

$a_n=-3(3)^{n-1}$ ; {-3,-9, -27,- 81, -243, ...}

$a_n=-3(-3)^{n-1}$ ; {-3, 9,-27, 81, -243, ...}

$a_n=3(\frac{1}{2})^{n-1}$ ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

$a_n=243(\frac{1}{3})^{n-1}$ ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

$a_n=-3(3)^{n-1}$

At n=1,

$a_1=-3(3)^{1-1}=-3$

At n=2,

$a_2=-3(3)^{2-1}=-9$

At n=3,

$a_3=-3(3)^{3-1}=-27$

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

$a_n=-3(-3)^{n-1}$

At n=1,

$a_1=-3(-3)^{1-1}=-3$

At n=2,

$a_2=-3(-3)^{2-1}=9$

At n=3,

$a_3=-3(-3)^{3-1}=-27$

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

$a_n=3(\frac{1}{2})^{n-1}$

At n=1,

$a_1=3(\frac{1}{2})^{1-1}=3$

At n=2,

$a_2=3(\frac{1}{2})^{2-1}=1.5$

At n=3,

$a_3=3(\frac{1}{2})^{3-1}=0.75$

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

$a_n=243(\frac{1}{3})^{n-1}$

At n=1,

$a_1=243(\frac{1}{3})^{1-1}=243$

At n=2,

$a_2=243(\frac{1}{3})^{2-1}=81$

At n=3,

$a_3=243(\frac{1}{3})^{3-1}=27$

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0

3 years ago