Question

The length of the rectangle is x cm. The length of a diagonal of the rectangle is 8 crn. The perimeter of the rectangle is 20 cm. Show that ia + 91 +b=0 where a and b are integers to be found.​

Answer 1

Answer:

$x^2-10x+18=0$

a = -10 and b = 18.

Step-by-step explanation:

Let w represent the width of the rectangle.

We are given that the perimeter of the rectangle is 20 cm, this means that:

$20=2(x + w)$

Let's put w in terms of x. Divide both sides by two:

$10=x+w$

And solve for w:

$w=10-x$

So, the rectangle measures x by (10 - x) cm.

According to the Pythagorean Theorem:

$a^2+b^2=c^2$

a and b are the legs and c is the hypotenuse.

Substitute x for a, w for b, and 8 for c:

$x^2+w^2=8^2$

Simplify and substitute:

$x^2+(10-x)^2=64$

Square:

$x^2+(100-20x+x^2)=64$

Isolate the equation. So:

$2x^2-20x+36=0$

Since the leading coefficient is one, divide both sides by two:

$x^2-10x+18=0$

Therefore, a = -10 and b = 18.