Because the parabola intercepts the x-axis only once, we conclude that the discriminant is 0.
<h3>
What can we say about the discriminant?</h3>
For a quadratic equation:
y = a*x^2 + b*x + c
The discriminant is:
D = b^2 - 4ac
- If D = 0, there is only one real zero.
- If D > 0, there are two real zeros.
- If D < 0, there are two complex zeros.
In the graph we can see that the parabola intercepts the x-axis in its vertex, then the parabola has only one real zero, then we conclude that the discriminant is equal to zero.
If you want to learn more about quadratic equations:
brainly.com/question/776122
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Answer:
37
Step-by-step explanation:
To find the answer to this equation, we need to substitute 5 into where x is in the original equation.
f(x) = 8x-3
f(5) = 8(5)-3
f(5)= 40-3
f(5)= 37
and that's it! no further simplifying.
I'm assuming that you meant:
1
f(x) = -------- and that you want to find the value of x at which f(x) = h(x).
x+1
Of course you could create a table for each f(x) and h(x), but setting f(x)=h(x) and solving for x algebraically would be faster and more efficient:
1
f(x) = -------- = 2x + 3 = h(x). Then 1 = (x+1)(2x+3) = 2x^2 + 3x + 2x + 3
x+1
or 1 = 2x^2 + 5x + 3, or 2x^2 + 5x + 2 = 0.
This is a quadratic equation with a=2, b=5 and c=2. The discriminant is b^2-4ac, or 5^2-4(2)(2), OR 25-16= 9.
Thus, the roots are
-5 plus or minus sqrt(9)
x = ------------------------------------
2(2)
-5 plus or minus 3
= ----------------------------------
4
= {-1/2, -2}
Thus, f(x) = h(x) at both x=-1/2 and x= -2.
Well if its compounded annually
<span><span>End Balance$18,492.79
</span><span>Total Principal$13,950.00
</span><span>Total Interest<span>$4,542.79</span></span></span>
