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horrorfan [7]
3 years ago
10

Stan is making a trail mix that has a combination of peanuts and raisins. The mix is three parts peanuts and one part raisins.Ho

w many cups of raisins does he need to use for a 16-cup recipe?
Mathematics
2 answers:
polet [3.4K]3 years ago
8 0
4 cups. 3+1=4 raisins are 1/4 and 1/4 of 16 is 4
denpristay [2]3 years ago
4 0
4 is the answer to ur questsion
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A cone has a diameter of 18 inches. and a height of 14 inches. What is the volume of the cone?
Andru [333]
Volume of cone is (1/3)π r² h.

So since diameter is 18 inches, radius is 9 inches, right?

So just plug in values and calculate;

V = (1/3)·π·9²·14
   = 378π
   ≈ 1187.52
5 0
3 years ago
CosA + cosB + cosC = 1 + 4sinA/2 sinB/2 sinC/2
bulgar [2K]

\cos(A)  +  \cos( B )  +  \cos(C)  \\  = 2 \cos( \frac{A + B}{2} )  \cos( \frac{ A- B}{2} )  + 1 - 2 { \sin }^{2}  \frac{C}{2}  \\  = 1 + 2\cos( \frac{\pi - C}{2} )   \cos( \frac{A - B}{2} )  - 2 { \sin }^{2}  \frac{C}{2}  \\  = 1 + 2 \sin \frac{C}{2}  \cos( \frac{A - B}{2} )  - 2 { \sin }^{2}  \frac{C}{2}  \\  = 1 + 2 \sin \frac{C}{2} [ \cos( \frac{A - B}{2} ) - \sin \frac{C}{2}]  \\  =  1 + 2 \sin \frac{C}{2} [ \cos( \frac{A - B}{2} ) - \cos( \frac{A  +  B}{2} )] \\  = 1 + 2 \sin\frac{C}{2} \times 2 \sin( \frac{ \frac{A + B}{2}  +\frac{A  -  B}{2} }{2} )  \sin( \frac{ \frac{A + B}{2}   - \frac{A  -  B}{2} }{2} )  \\  = 1 + 4 \sin \frac{A}{2}  \sin \frac{B}{2}  \sin \frac{C}{2}

6 0
3 years ago
Graph the linear equation 3x - y = 12. Write the equation in slope-intercept form,
S_A_V [24]

Answer: y=3x-12

Step-by-step explanation:

5 0
3 years ago
James measured a piece of construction paper to be 6 3/4 inches wide and 9 2/3 inches long. What is the area of the piece of con
ivolga24 [154]

Answer:

The area of the piece of construction paper is \frac{261}{4} inches^2

Step-by-step explanation:

Length of construction paper =6 \frac{3}{4} inches

                                                 =\frac{27}{4} inches

Width of construction paper = 9 \frac{2}{3} inches

                                              = \frac{29}{3} inches

Area of construction paper =Length \times Width

Area of construction paper = \frac{27}{4}  \times \frac{29}{3}

                                             = \frac{261}{4} inches^2

Hence the area of the piece of construction paper is \frac{261}{4} inches^2

7 0
3 years ago
FILL IN THE BLANK TO MAKE THE NUMBER SENTENCE TRUE.<br><br> 6 X 2/<br> = 6
mel-nik [20]
6 x 2/2 = 6, because 2/2 is 1 and 6x1 is 6
3 0
2 years ago
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