Question

Please help me with it is for homework I really need help please help me

Answer 1

Answer:

See explanation

Step-by-step explanation:

Given two expressions:

$2(s+0.5)+2(s+1.5)$

and

$4\left(\dfrac{1}{2}s+\dfrac{1}{4}s\right)+4$

a. When $s=0,$

then

$2(s+0.5)+2(s+1.5)=2(0+0.5)+2(0+1.5)=1+3=4$

and

$4\left(\dfrac{1}{2}s+\dfrac{1}{4}s\right)+4=4\left(\dfrac{1}{2}\cdot 0+\dfrac{1}{4}\cdot 0\right)+4=4$

b. When $s=12,$

then

$2(s+0.5)+2(s+1.5)=2(12+0.5)+2(12+1.5)=2\cdot 12.5+2\cdot 13.5=25+27=52$

and

$4\left(\dfrac{1}{2}s+\dfrac{1}{4}s\right)+4=4\left(\dfrac{1}{2}\cdot 12+\dfrac{1}{4}\cdot 12\right)+4=4(6+3)+4=4\cdot 9+4=36+6=40$

c. Since the value of both expressions at s = 12 are different, the expressions are not equivalent.