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Citrus2011 [14]
3 years ago
12

Use all the six numerals 4, 5, 6, 7, 8 and 9 to form two 3-digit even numbers whose sum is smallest, and what is the sum? ​

Mathematics
1 answer:
tamaranim1 [39]3 years ago
8 0

9514 1404 393

Answer:

  476 +598 = 1074

Step-by-step explanation:

In order for the sum to be smallest, the two most-significant digits must be the smallest possible. That is, they must be 4 and 5.

The two least-significant digits must be even. The remaining even digits are 6 and 8. Then the tens digits are the digits left over: 7 and 9.

Possible sums are ...

  476 +598 = 1074

  478 +596 = 1074

  496 +578 = 1074

  498 +576 = 1074

The sum is 1074.

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9. Determine whether or not the number 257 is prime.
Sladkaya [172]

Answer:

257 is prime.

Step-by-step explanation:

To evaluate if a number is prime, we just need to evaluate it for the prime numbers that are equal or lesser than the said number's square root.

In this case, √257 = 16.03 so we just need to see if 257 is divisible by <u>2, 3, 5, 7, 11 and 13</u> (the prime numbers that come before 16)

  • 257 is odd, so it is not divisible by 2.
  • The sum of its digits is 14, therefore, it is not divisible by 3.
  • 257 ends in 7, therefore it's not divisible by 5.
  • 257/ 7 = 36.71 so it's not divisible by 7.
  • 257/ 11 = 23.36 so it's not divisible by 11
  • Finally 257 / 13= 19.76 so it's not divisible by 13.

Therefore, 257 is prime.

7 0
3 years ago
I NEEED HELP NOW PLEASA
ZanzabumX [31]

Answer: The answer will be 28


Step-by-step explanation:


3 0
3 years ago
Anybody know the answer?
maksim [4K]

x is 3pi/4 and 7pi/4

Type in correctly

8 0
3 years ago
Solve: x ÷ 0.6 = 8.9<br><br><br> 5.34<br><br><br> 9.5<br><br><br> 8.3<br><br><br> 0.07
Basile [38]

Answer: x = 0.6 ÷ 8.9 = 5.34

Step-by-step explanation:

5 0
3 years ago
A house that was originally listed for sale at $450,000 has decreased the asking price by 8%. By how much has the price been red
matrenka [14]
450000 * .08
= 36,000
They reduce $36,000 from the original price.
5 0
3 years ago
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