Use all the six numerals 4, 5, 6, 7, 8 and 9 to form two 3-digit even numbers whose sum is smallest, and what is the sum?
1 answer:
9514 1404 393
Answer:
476 +598 = 1074
Step-by-step explanation:
In order for the sum to be smallest, the two most-significant digits must be the smallest possible. That is, they must be 4 and 5.
The two least-significant digits must be even. The remaining even digits are 6 and 8. Then the tens digits are the digits left over: 7 and 9.
Possible sums are ...
476 +598 = 1074
478 +596 = 1074
496 +578 = 1074
498 +576 = 1074
The sum is 1074.
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Chur best answer is gonna be B hope this helps chu
Answer:
C
All Real Numbers, this is because it has infinitely MANY solutions.
Step-by-step explanation:
Answer:
Dónde está
Step-by-step explanation:
m<PQS = m<SQR
4y - 10 = 2y + 10
2y = 20
y = 10
m<PQR = m<PQS + m<SQR
= 4y - 10 + 2y + 10
= 6y
= 6•10
= 60
Answer:
option A
Step-by-step explanation:
To Test
H₀ : μ = 3.75
H₁ : μ ≠ 3.75
now,
If μ = 3.95 then it means H₀ is not true.
then the probability is rejecting the null hypothesis.
Hence, the probability is the power of the test against the alternative μ=3.95
The correct answer is option A
