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3 years ago

5

2":12"::6":24" Is this a true proportion?

1 answer:

Nata [24]3 years ago

7 0

No, it's not a function because 2*6=12, but 6*4=24. In order for it to be an actual proportion, it would have to have the same number multiplied to it. Hope this helps!

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An equation is shown below:

stepladder [879]

There is no solution to the equation.
The x is cancelled out.

See attachment file below.

Hope it helped!

5 0

3 years ago

Can help me for homework pleas

Rasek [7]

Hey You!

32 / 8 = 4

4 × 7 = 28

20. ANSWER:

The fish swims 28 feet deep.

21. ANSWER:

Numerator;Denominator

22. ANSWER:

439 / 3 = 146.3333 repeat.

So, each individual computer costs more than each individual printer.

6 0

3 years ago

Read 2 more answers

Do ya'll know how to do this? (grade 10) <br><br> Please help im stranded :(<br><br> (15 Points)

dimulka [17.4K]

Answer:

a.) (-16,0)(0,12)

b.) (-3,0)(0, 3/2)

Step-by-step explanation:

Plug it in for each.

y= 3/4x+12 (Lets plug in our x intercept of (x,0) and our y intercept of (0,y)

x-intercept

0=3/4x+12

-12 -12

-12=3/4x

-12/(3/4)=x

-16=x

SO, your x intercept is -16 which is point (-16, 0)

Now to do your y intercept in lets plug x in as 0 instead this time:

y = 3/4(0)+12

y = 12

Your y intercept is 12

Now for b its the same process of plugging 0 in for the values let

y-int=-2(0)-4y+6=0

-6 -6

-4y/-4=-6/-4 <- divide both sides by 4

y = 3/2 <- Simplified answer

y int = (0, 3/2)

x-int = -2x-4(0)+6 = 0

+6 +6

-2x = 6

x = 6/-2 <-- Divide both sides by -2

x = -3 <-- Simplify

x-int = (-3, 0)

5 0

3 years ago

What is the quotient?

exis [7]

The quotient is $\frac{3(y-5)}{2}$

Explanation:

The expression is $\frac{2 y^{2}-6 y-20}{4 y+12} \div \frac{y^{2}+5 y+6}{3 y^{2}+18 y+27}$

Now, reciprocal the term $\frac{y^{2}+5 y+6}{3 y^{2}+18 y+27}$ and convert ÷ to ×

$\frac{2 y^{2}-6 y-20}{4 y+12} \times \frac{3 y^{2}+18 y+27}{y^{2}+5 y+6}$

Taking the common terms out, we get,

$\frac{2\left(y^{2}-3 y-10\right)}{4(y+3)} \times \frac{3\left(y^{2}+6 y+9\right)}{y^{2}+5 y+6}$

Factorizing each numerator and denominator, we get,

$\frac{2(y-5)(y+2)}{4(y+3)} \times \frac{3(y+3)(y+3)}{(y+3)(y+2)}$

Multiplying the terms, we have,

$\frac{6(y-5)(y+2)(y+3)^{2}}{4(y+3)^{2}(y+2)}$

Cancelling the common factors, we get,

$\frac{3(y-5)}{2}$

Thus, the quotient is $\frac{3(y-5)}{2}$

8 0

3 years ago

Write a compound inequality where A quantity x is at least 10 and at most 20

inna [77]

<h3><u>20 ≥ x ≥ 10</u></h3>

would the way to display the compound inequality.

3 0

4 years ago