<span>20x + 12y = 1040
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-12y' to each side of the equation.
20x + 12y + -12y = 1040 + -12y
Combine like terms: 12y + -12y = 0
20x + 0 = 1040 + -12y
20x = 1040 + -12y
Divide each side by '20'.
x = 52 + -0.6y
thats the first part
then we have
</span>25x + 16y = 1350
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-16y' to each side of the equation.
25x + 16y + -16y = 1350 + -16y
Combine like terms:
16y + -16y = 0
25x + 0 = 1350 + -16y
25x = 1350 + -16y
Divide each side by '25'.
x = 54 + -0.64y
Answer:
a = 80
b = 40
c = 58
d = 19
e = 34
f = 36
Pls mark brainliest. Thanks!
V=9 1/20, because when you multiply 4/5 by 4 and 1/4 by 5 to get a common denominator you get 21/20. You add the 3 and the 5, and add the one we got from the fractions and add the 1/20 to get 9 1/20
Answer:
The Amount of money in the account after 28 years is $616,674.5
Step-by-step explanation:
Given as :
The principal amount placed in the account = p = $67,000
The rate of interest = r = 8.25%
The time period of amount in the account = t = 28
Let the Amount of money in the account = $A
Now<u>, From Compound Interest method</u>
Amount = Principal × 
A = p × 
Or, A = $67,000 × 
Or, A = $67,000 × 
Or, A = $67,000 × 9.2041
∴ A = $616,674.7
So, The Amount of money in the account = A = $616,674.5
Hence, The Amount of money in the account after 28 years is $616,674.5 Answer
