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nignag [31]
3 years ago
5

Sebuah tangga yang panjangnya 5m bersandar pada dinding rumah. Tinggi dinding yang di capai tangga tersebut adalah 3,5m, jarak u

jung bawah tangga terhadap dinding?

Mathematics
1 answer:
timofeeve [1]3 years ago
3 0

Answer:

x≅3.57m

Step-by-step explanation:

Kami menerapkan teorema kaki

a^{2}+b^{2}=c^{2}\\   mengganti\\x^{2}+(3.5)^{2}=5^{2}\\x^{2}=5^{2}-(3.5)^{2}\\x^{2}=25-12.25\\x=\sqrt{25-12.25}=3.57m

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Which choice is equivalent to the expression below?<br>√-64​
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Answer:

The answer is option A.

√-64 = 8i

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6 0
4 years ago
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Simplify the expression:<br> 8g2–3g2+g2
Olin [163]

Answer:

Transform your question to : 8g2 - 3g2 - 1g2

"We added a 1 to the last g2 and it became 1g2"

So now I'm just gonna give you the answer I got.

8g2 - 3g2 - 1g2

= 4g2

Solution: 4g2

Step-by-step explanation:

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8 0
3 years ago
Which pair is equivalent? 5/4 &amp; 1 2/4 . 4 6/7 &amp; 7/34. 3 3/5 &amp; 18/5. 12/9 &amp; 2 3/9​
Drupady [299]

3 3/5 & 18/5 are both equivalent

Step-by-step explanation:

3 3/5 = 18/5

<u>Write the mixed number as an improper fraction</u>

Step 1: Multiply the denominator by the whole number

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Step 2: Add the answer from Step 1 to the numerator

15 + 3 = 18

Step 3: Write answer from Step 2 over the denominator

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8 0
3 years ago
C - x = r - d , for x
zysi [14]

Answer:

x = C+d-r

Step-by-step explanation:

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x = -(r - d - C)

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8 0
3 years ago
A computer consulting firm presently has bids out on three projects. Let Ai = {awarded project i}, for i = 1, 2, 3, and suppose
Karo-lina-s [1.5K]

Step-by-step explanation:

The data below is what was provided in the question and it is what I solved the question with

P(A1) = 0.23

P(A2) = 0.25

P(A3) = 0.29

P(A1 n A2 ) = 0.09

P(A1 n A3) = 0.11

P(A2 n A3) = 0.07

P(A1 n A2 n A3) = 0.02

a

P(A2|A1) = P(A1 n A2)/P(A1)

= 0.09/0.23

= 0.3913

We have 39.13% confidence that event A2 will occur given that event A1 already occured

b.)

P(A3 n A3|A1) = P(A2 n A3)n A1)/P(A1)

= 0.02/0.23

= 0.08695

We have about 8.7% chance of events A2 and A3 occuring given that A1 already occured.

C.

P(A2 u A3|A1)

= P(A1 n A2)u(A1 n A3)/P(A1)

= P( A1 n A2) + P(A1 n A3) - P(A1 n A2 n A3) / P(A1)

= (0.09+0.11-0.02)/0.23

= 0.18/0.23

= 0.7826

We have 78.26% chance of A2 or A3 happening given that A1 has already occured.

6 0
3 years ago
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