Answer:
Vertical Asymptote:

Horizontal asymptote:
it does not exist
Step-by-step explanation:
we are given

Vertical asymptote:
we know that vertical asymptotes are values of x where f(x) becomes +inf or -inf
we know that any log becomes -inf when value inside log is zero
so, we can set value inside log to zero
and then we can solve for x

we get

Horizontal asymptote:
we know that
horizontal asymptote is a value of y when x is +inf or -inf
For finding horizontal asymptote , we find lim x-->inf or -inf



so, it does not exist
<em>Lets say that √(3+i) is the magnitude of your vector. In polar form, i represents the x component and j represents the y component of the vector. Therefore, the polar form is icosθ√(3+i) + jsinθ√(3+i)</em>
draw a diagram :
<em>z = r(cos θ + i sin θ), where z = complex number, r = modulus, θ = angle of rotation For the given:r = 2θ = π/6 √3 + i = 2(cos π/6 + i sin π/6)</em>
<em>hope</em><em> </em><em>thz</em><em> </em><em>hlpz</em><em> </em><em>✿</em>
Answer:
f(x)=-|x|
Step-by-step explanation:
We have been given a graph of f(x) which resembles with the graph of function g(x) where g(x)=|x|.
It says that graph is flipped over the x-axis.
Now we have to find about which of the following choice correctly describes the given graph.
We know that |x| means absolute value of x so that means g(x)=|x| is absolute function in shape of V.
We know that flipping over x-axis can be done by changing f(x) into -f(x).
<u>Hence correct answer is choice D) F(x)=-|x|</u>
Connect each median to point R point S this will help to figure out where exactly to draw the medians. Hope that helps please say brainliest
Answer:
I think A and C
Step-by-step explanation: