Answer:
p-value: 0.0367
Decision: Reject H₀
Step-by-step explanation:
Hello!
Hypothesis to test:
H₀:ρ₁-ρ₂=0
H₁:ρ₁-ρ₂>0
The statistic to use to test the difference between two population proportions is the approximation of Z
Z=<u> (^ρ₁-^ρ₂)-(ρ₁-ρ₂) </u> ≈N(0;1)
√ (<u>^ρ₁(1-^ρ₁))/n₁)+(^ρ₂(1-^ρ₂)/n₂))</u>
Z=<u> (0.28-0.15)-0 </u>= 1.79
√ (<u>0.28(1-0.28)/200)+(0.15(1-0.15)/300)</u>
p-value
Remember: The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis).
P(Z>1.79)= 0.0367
Conclusion:
Comparing the p-value against the significance level, you can decide to reject the null hypothesis.
I hope you have a SUPER day!
Length = x + 2 (because it is 2 cm more than x)
Width = 2x - 5 (5 cm lest than 2x)Area = 54 cm2 this is the formula to find the area Length × Width = Area (x + 2)(2x - 5) = 542x2 - x - 10 = 54 (this is you area)
Subtract 54 on both sides of equation to make the right side zero. 2x2 - x - 64 = 0 then use the quadratic formula x = (-b ± √(b2 - 4ac)) / 2a where:a = 2b = -1c = -64 Plug in these values into the formula. x = (1 ± √(1 - 4(-128))) / 4 x = (1 ± √(513)) / 4 x = (1 ± 22.65) / 4 x = (1 + 22.65) / 4 and x = (1 - 22.65) / 4 x = 5.91 and x = -5.41 Check the validity of the x values by adding them to the length and width. If the length or width should be a negative value, then that value of x is not acceptable. Now x = 5.91 Length = 5.91 + 2 (positive value.)Width = 2(5.91) - 5 ( positive value.) x = 5.91 If we look at this -- x = -5.41, Both length and width will be negative values. We reject this value of x. The answer is x = 5.91
Hope I helped and sorry it was really long
7 <span> more than 3 times a number </span>
<span>more than is code for + </span>
<span>times is multiply </span>
<span>so 7+3n=31 </span>
<span>solve: </span>
<span>3n=24 </span>
<span>n= 8</span>
Answer:
number one is the appropriate answer for this question
Can you provide me with a picture so that I can help you answer this question?
