Question

If a programming language does not use short-circuit evaluation, what is the output of the following code fragment if the value of myInt is 0?int other=3, myInt;if(myInt !=0 && other % myInt !=0)cout << "other is odd\n";elsecout << "other is even\n";
a.other is even
b.other is odd
c.0
d.run-time error, no output

Answer 1

Answer:

Run time error, no output. If myInt = 0 and other is 3, then 3%0 will never occur...apart from that, myInt was neither declared nor initialized

Explanation: