Newspapers will continue to collapse or have their newsroom staffs substantially reduced as a result of their excessive debt.
One of these was advocacy journalism, where the journalist actively advances a specific cause or point of view. Early American newspapers were partisan and sensational, but in the late nineteenth and early twentieth century, they started to become more objective and professional. Many journalists have been confused by the fall in recent years since readers don't seem to be all that interested in reading newspapers. The decline in newspaper production is caused by a number of factors, including social media, corporate ownership, internet access, and advertising. Three of the four primary purposes of mass communication—surveillance, correlation, and cultural transmission—involve journalism to a significant extent.
Learn more about professional here-
brainly.com/question/1938929
#SPJ4
Co-Ordination Difficulty: ...
Waste of Resources: ...
Larger Interests of the Enterprise Neglected: ...
Emergency Decision not Possible: ...
Lack of Qualified Managers: ...
Certain Activities Decentralization not Possible:
Either A or B. I would go with A but It can actually be B
Answer:
Language programming Web's programming language
Explanation:
Answer:
1.
class TIME
{
int hour , min , sec ;
public :
TIME()
{
hour=min=sec=0;
}
TIME( int h , int m , int s )
{
hour = h;
min = m;
sec = s;
}
void change ( int Hour)
{
hour = Hour;
}
void stdtime()
{
if(hour>12)
cout<<"The Standard time is"<<(hour-12)<<":"<<min<<":"<<sec<<"P.M\n";
else
cout<<"The Standard time is"<<hour<<":"<<min<<":"<<sec<<"A.M\n";
}
void miltime()
{
cout<<"The Military time is"<<hour<<":"<<min<<":"<<sec<<" hours\n";
}
};
void main()
{
TIME A , B(13,25,30);
A .stdtime();
A.change(23);
A.miltime();
B.stdtime();
B.change(9);
B.miltime();
}
2.
class elevator
{
int CurrentFloor;
int GoingUp;
int GoingDown;
public:
elevator()
{
CurrentFloor=0;
GoingUp=1;
GoingDown=-1;
}
elevator(int floor)
{
CurrentFloor=floor;
GoingUp=1;
GoingDown=-1;
}
void goUp(int y)
{
if( CurrentFloor>3)
cout<<"\nNO MORE FLOORS\n";
else
CurrentFloor=CurrentFloor+y*GoingUp;
}
void goDown(int x)
{
if(CurrentFloor<0)
cout<<"\nNO MORE FLOORS";
else
CurrentFloor=CurrentFloor+x*GoingDown;
}
};
void main()
{
elevator A(1);
A.goUp(1);
A.goUp(1);
A.goUp(1);
A.goDown(1);
A.goDown(1);
}