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Deffense [45]
3 years ago
11

At the amusement park Laura paid 6.00 for a small cotton candy her older brother works at the park and he told her that they mar

k up the cotton candy by 300% Laura does not think that is mathematically possible is it possible and if so what is the price of the cotton candy before the markup
Mathematics
1 answer:
Rudiy273 years ago
8 0
That would mean 6 is 3 times the original price, 6 is divisible by 3 so it is possible and the price would be 2.00

Hope this helps :)
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S = ut+ 16t²<br>Find the value of s when u = 2 and t = 3.​
Fed [463]

Answer:

<h2>150</h2>

Step-by-step explanation:

Given,

u = 2

t = 3

Now, Finding the value of s

s = ut \:  + 16 {t}^{2}

Plugging the values of u and t

s = 2 \times 3 + 16 \times  {( 3)}^{2}

Calculate

s = 2 \times 3 + 16 \times 9

s = 6 + 144

Calculate the sum

s = 150

Hope this helps ..

Good luck on your assignment..

4 0
3 years ago
Read 2 more answers
How to solve exterior angle for right triangle?
denis23 [38]
Attached the solution and work.

5 0
3 years ago
What is the circumference of quadrilateral ABED in cm?
Natasha2012 [34]

the perimeter of quadrilateral ABED is 36.

<h3 /><h3>What is circumference?</h3>

A circumference is the total distance around a plane shape. Another name for circumference is called perimeter

To calculate the circumference of the quadrilateral, we use the formula below.

Formula:

  • Peri. of ABED = /AB/+/BE/+/ED/+/DA/............. Equation 1

From the Diagram,

Given:

  • /AB/ = /DC/ = 8 cm,
  • /BE/ = 2×/DA/ = 2×6 = 12 cm
  • /ED/ = √(6²+8²) = √(36+64) = √100 = 10 cm
  • /DA/ = 6 cm

Substitute these values into equation 1

  • Peri. of quadrilateral ABED = 8+12+10+6
  • Peri. of quadrilateral ABED  = 36 cm

Hence, the perimeter of quadrilateral ABED is 36.

Learn more about circumference here: brainly.com/question/20489969

#SPJ1

4 0
2 years ago
Evaluate the expression
fgiga [73]
Simplify the following:
2^3 (4×36/12 + 1/4)

4×36/12 = (4×36)/12:
2^3 ((4×36)/12 + 1/4)
2^3 = 2×2^2:
2×2^2 ((4×36)/12 + 1/4)
2^2 = 4:
2×4 ((4×36)/12 + 1/4)
2×4 = 8:
8 ((4×36)/12 + 1/4)
36/12 = (12×3)/12 = 3:
8 (4×3 + 1/4)
4×3 = 12:
8 (12 + 1/4)
Put 1/4 + 12 over the common denominator 4. 1/4 + 12 = 1/4 + (4×12)/4:
8 1/4 + (4×12)/4
4×12 = 48:
8 (1/4 + 48/4)
1/4 + 48/4 = (1 + 48)/4:
8 (1 + 48)/4
1 + 48 = 49:
8×49/4

8×49/4 = (8×49)/4:
(8×49)/4
8/4 = (4×2)/4 = 2:
2×49
2×49 = 98:
Answer: 98
4 0
4 years ago
What happens to the distance between each billiard ball during this rigid<br><br> transformation?
Delicious77 [7]

The question is incomplete. Here is the complete question.

To set up a game of billiards, the first player moves the balls contained within a triangular rack as shown. What happens to the distance between each billiard during this rigid transformation?

A. The distance remains constant throughout the transformation.

B. The distance decreases at the start and increases after all motion stops.

C. The distance stays the same at the start but decreasesexactly when motion ends.

D. The distance increases at the start and then decreases as the rack gets further from the player.

Answer: A. The distance remains constant throughout the transformation.

Step-by-step explanation: In a <u>rigid</u> <u>motion</u>, all moving points in the plane are moving in way such tha:

1)  relative distance between them stays the same and

2) relative position of the points stays the same

There are four types of rigid motions: translation, rotation, reflexion and glide reflection.

<u>Translation</u>: every point or object is moved by the same amount and in the same direction;

<u>Rotation</u>: the object rotates by the same amount around a fixed point;

<u>Reflexion</u>: the object exchange points from one side of a line with points on the other side of the line at the same distance from the line;

<u>Glide</u> <u>Reflection</u>: is a mirror reflection followed by a translation parallel to the mirror.

In the game of billiards, because all the balls are inside the triangular rack, the distance, and also the position, between them stays the same, limited by the rack. Since they are moving by the same amount in the same direction, the rigid transformation is a translation.

Therefore, the distance of the balls in the triangular rack remains constant throughout the transformation.

6 0
3 years ago
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