3 years ago

A system of equations with a linear and quadratic equation must have two solutions.

Mathematics

1 answer:

aliina [53]3 years ago

6 0

This is false

Sometimes these kinds of system can have 0 answers, or just 1, so it's incorrect that 2 are a must.

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1. -3 2/5 + b = 8 1/5 2. -7/3 n = -42 PLZ HELP ASAP I WILL MARK BRAINLIEST

diamong [38]

1. Convert the mixed numbers into improper numbers (-3 2/5 = -17/5 and 8 1/5 = 41/5). Then add 17/5 to both sides when means b=58/5

2. Multiply both sides by the reciprocal of -7/3 (which is -3/7). So n=18

7 0

2 years ago

-x - 1 = 221 + 2x plzzzzzzzzz help

Otrada [13]

$Simplifying
-1x + -1 = 221 + 2x

Reorder the terms:
-1 + -1x = 221 + 2x

Solving
-1 + -1x = 221 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
-1 + -1x + -2x = 221 + 2x + -2x

Combine like terms: -1x + -2x = -3x
-1 + -3x = 221 + 2x + -2x$
$Combine like terms: 2x + -2x = 0
-1 + -3x = 221 + 0
-1 + -3x = 221

Add '1' to each side of the equation.
-1 + 1 + -3x = 221 + 1

Combine like terms: -1 + 1 = 0
0 + -3x = 221 + 1
-3x = 221 + 1

Combine like terms: 221 + 1 = 222
-3x = 222

Divide each side by '-3'.
x = -74

Simplifying
x = -74$