A triangle with side lengths of 5, 5, and 8 is:

2000 soldiers stand in a row. Beginning from the left, each soldier calls out a number, 1, 2, 3, 1, 2, 3, 1, 2, 3, 1, 2, 3, and

Cloud [144]

Answer:

The number of soldiers that call out a number 3 is 666 soldiers

Step-by-step explanation:

The parameters given are;

Number of soldiers = 2000

Soldiers calling from the left = 1, 2, 3,.....

Soldiers calling from the right = 1, 2, 3,.....

Therefore, since the number soldiers calling out the number 3 are 1 in 3 from the left and 1 in 3 from the right, we split the soldiers into 2 groups of 1000, with one group calling from left and the other group calling from the right;

The number of 3s in called out in the first group from the left is therefore;

1000/3 = 333.33 which is 333 soldiers or from the 3rd soldier to the 999th soldier

Similarly the number of 3s called out from the second group = 333

Hence the total number of soldiers that call out a number 3 = 333 + 333 = 666 soldiers.

8 0

3 years ago

When consumers apply for credit, their credit is rated using FICO (Fair, Isaac, and Company) scores. Credit ratings are given be

Flura [38]

Answer:

a) The 99% confidence interval would be given by (589.588;731.038)

b) If we see the confidence interval the 620 is included on the interval we don't have enough evidence to reject the rating is 620. But since we need a score that at least 620 and our lower limit is 589.588 we cant conclude that all the clients would have a score that at least of 620.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The data is:

661 595 548 730 791 678 672 491 492 583 762 624 769 729 734 706

Part a

Compute the sample mean and sample standard deviation.

In order to calculate the mean and the sample deviation we need to have on mind the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$

=AVERAGE(661, 595, 548, 730, 791, 678, 672, 491 ,492, 583, 762 ,624 ,769, 729, 734, 706)

On this case the average is $\bar X= 660.313$

=STDEV.S(661, 595, 548, 730, 791, 678, 672, 491 ,492, 583, 762 ,624 ,769, 729, 734, 706)

The sample standard deviation obtained was s=95.898

Find the critical value t* Use the formula for a CI to find upper and lower endpoints

In order to find the critical value we need to take in count that our sample size n =16<30 and on this case we don't know about the population standard deviation, so on this case we need to use the t distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . The degrees of freedom are given by:

$df=n-1=16-1=15$

We can find the critical values in excel using the following formulas:

"=T.INV(0.005,15)" for $t_{\alpha/2}=-2.95$

"=T.INV(1-0.005,15)" for $t_{1-\alpha/2}=2.95$

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$

And if we find the limits we got:

$660.313- 2.95\frac{95.898}{\sqrt{16}}=589.588$

[tex]660.313+ 2.95\frac{95.898}{\sqrt{16}}=731.038/tex]

So the 99% confidence interval would be given by (589.588;731.038)

Part b

If we see the confidence interval the 620 is included on the interval we don't have enough evidence to reject the rating is 620. But since we need a score that at least 620 and our lower limit is 589.588 we cant conclude that all the clients would have a score that at least of 620.

4 0

3 years ago

Each student in your class tosses a coin. The result of each toss is either heads or tails.

Alenkasestr [34]

Answer:

b

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Suppose the linear regression line y=2.1x+130 predicts sales based on the money spent on advertising. If x represents the dollar

slega [8]

Linear regression line y=2.1x+130 predicts sales based on the money spent on advertising.

Linear regression represents the relationship between two variables. the value of y depends on the value of x.

x represents the dollars spent in advertising and y represents the company sales in dollars.

We need to find out sales y when $150 spends on advertising.

Plug in 150 for x and find out y

y = 2.1 x + 130

y = 2.1 (150) + 130

y= 445

The company expects $445 in sales

5 0

3 years ago

Pineapples cost $2.50 each and mangos cost $1.50 each. Tim purchased 15 pieces of fruit for $29.50. How many pineapples and how

kotykmax [81]

We can create equations to solve this.

2.50p + 1.50m = 29.50
p + m = 15

Solve for a variable in the 2nd equation and use the substitution method to solve.

p + m = 15

Subtract p to both sides:

m = -p + 15

Plug in -p + 15 for m in the first equation.

2.50p + 1.50(-p + 15) = 29.50

Distribute:

2.50p - 1.50p + 22.50 = 29.50

Combine like terms:

p + 22.50 = 29.50

Subtract 22.50 to both sides:

p = 7

Now plug this into any of the two equations and solve for the other variable.

p + m = 15

7 + m = 15

Subtract 7 to both sides:

m = 8

So he purchased 7 pineapples and 8 mangos.

4 0

3 years ago