Marco's polo team has a budget for new uniforms of $250. If there are 12 members of the team, what can Marco spend on uniforms.

A variety of two types of snack packs are delivered to a store. The box plots compare the number of calories in each snack pack

mote1985 [20]

Answer:D, “the number of calories...”

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

If x=y-7 what is the value of 3x-3 in terms of y

beks73 [17]

$\bf \boxed{x}=y-7
\\\\\\
3x-3\implies 3\left( \boxed{y-7} \right)-3\implies 3y-21-3\implies 3y-24$

7 0

2 years ago

Is it possible to build a triangle with inside angles of 90 degrees , 50 degrees, and 60 degrees?

N76 [4]

Answer:

No

Step-by-step explanation:

Given: Angles of a triangle are equal to 90 degrees , 50 degrees, and 60 degrees

To check : if it possible to build a triangle with given angles

Solution:

According to angle sum property of a triangle, sum of angles of a triangle is equal to $180^{\circ}$

Here,

sum of given angles = $90^{\circ}+50^{\circ}+60^{\circ}=200^{\circ}\neq 180^{\circ}$

Therefore, it is <u>not possible</u> to construct a triangle with given angles.

7 0

2 years ago

Horses age more rapidly than humans. Suppose that the “horse age” and “human age” vary directly, and suppose that a 5 year old h

Temka [501]

Well, lets start with what you know. We know that 5 horse years is equal to 15 human years. If the horse is 16, 5 times 3.2 equals 16.
5 year old horse/ 15 year old human
16 year old horse/ ? human?
3.2 times 5 is 16. To find the answer, do 3.2 times 15, or 320% of 15. Three times fifteen is 45. 20% of 16 is 3.2. 45 plus 3.2 is 47.2! Did this help you?

6 0

2 years ago

Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive

NeX [460]

Answer:

(a) 0.343

(b) 0.657

(c) 0.189

(d) 0.216

(e) 0.353

Step-by-step explanation:

Let P(a vehicle passing the test) = p

$p = \frac{70}{100} = 0.7$

Let P(a vehicle not passing the test) = q

q = 1 - p

q = 1 - 0.7 = 0.3

(a) P(all of the next three vehicles inspected pass) = P(ppp)

= 0.7 × 0.7 × 0.7

= 0.343

(b) P(at least one of the next three inspected fails) = P(qpp or qqp or pqp or pqq or ppq or qpq or qqq)

= (0.3 × 0.7 × 0.7) + (0.3 × 0.3 × 0.7) + (0.7 × 0.3 × 0.7) + (0.7 × 0.3 × 0.3) + (0.7 × 0.7 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.3)

= 0.147 + 0.063 + 0.147 + 0.063 + 0.147 + 0.063 + 0.027

= 0.657

(c) P(exactly one of the next three inspected passes) = P(pqq or qpq or qqp)

= (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

= 0.063 + 0.063 + 0.063

= 0.189

(d) P(at most one of the next three vehicles inspected passes) = P(pqq or qpq or qqp or qqq)

= (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7) + (0.3 × 0.3 × 0.3)

= 0.063 + 0.063 + 0.063 + 0.027

= 0.216

(e) Given that at least one of the next 3 vehicles passes inspection, what is the probability that all 3 pass (a conditional probability)?

P(at least one of the next three vehicles inspected passes) = P(ppp or ppq or pqp or qpp or pqq or qpq or qqp)

= (0.7 × 0.7 × 0.7) + (0.7 × 0.7 × 0.3) + (0.7 × 0.3 × 0.7) + (0.3 × 0.7 × 0.7) + (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

= 0.343 + 0.147 + 0.147 + 0.147 + 0.063 + 0.063 + 0.063

= 0.973

With the condition that at least one of the next 3 vehicles passes inspection, the probability that all 3 pass is,

$= \frac{P(all\ of\ the\ next\ three\ vehicles\ inspected\ pass)}{P(at\ least\ one\ of\ the\ next\ three\ vehicles\ inspected\ passes)}$

$= \frac{0.343}{0.973}$

= 0.353

3 0

3 years ago

Read 2 more answers