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Mandarinka [93]
3 years ago
11

A ball is thrown straight up into the air with a speed of 10 m/s . If the ball has a mass of 0.3 kg how high does the ball go ?

Physics
2 answers:
hichkok12 [17]3 years ago
8 0

Answer:

5.1

Explanation:

apex

Damm [24]3 years ago
5 0
<h3><u>Answer;</u></h3>

= 5.102 m

<h3><u>Explanation;</u></h3>

The total energy, i.e. sum of kinetic and potential energy, is constant.

That is; E = KE + PE

Initially, PE = 0 and KE = 1/2 mv^2

At maximum height, velocity=0, thus, KE = 0 and PE = mgh

Since, total energy is constant (KE converts to PE when the ball is rising).

Therefore, KE = PE

or, 1/2 mv^2 = mgh

or, h = v^2 /2g

        = 10^2 / (2x9.8)

        =<u> 5.102 m</u>

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The secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter. The turns ratio of t
Sphinxa [80]

Answer:

The power consumed by the air filter is 9.936 watts      

Explanation:

It is given that, the secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter.

Turn ratio of the transformer, \dfrac{N_s}{N_p}=\dfrac{46}{1}

Voltage of primary coil, V_p=120\ V

Current in the secondary coil, I_s=1.8\times 10^{-3}\ A

The power consumed by the air filter is :

P_s=I_s\times V_s...........(1)

For a transformer, \dfrac{N_s}{N_p}=\dfrac{V_s}{V_p}

So, P_s=I_s\times (\dfrac{N_s}{N_p})\times V_p

P_s=1.8\times 10^{-3}\times (\dfrac{46}{1})\times 120

P_s=9.936\ Watts

So, the power consumed by the air filter is 9.936 watts. Hence, this is the required solution.                

3 0
4 years ago
Read 2 more answers
Of waterfalls with a height of more than 50 m , Niagara Falls in Canada has the highest flow rate of any waterfall in the world.
Vinil7 [7]

Answer:

Power output: W=1426.9MW

Explanation:

The power output of the falls is given mainly by its change in potential energy:

Q=-P_{tot}=-(P_{2}-P_{1})

The potential energy for any point can be calculated as:

P=m*g*h

If we consider the base of the falls to be the reference height, at point 2 h=0, so P2=0, and height at point 1 equals 52m:

Q=P_{1}=m*g*h

If we replace m with the mass rate M we obtain the rate of change in potential energy over time, so the power generated:

W=M*g*h=2.8*10^{3}m^{3}/s*1*10^{3}kg/m^{3}*9.8m/s^{2}*52m =1426.9MW

5 0
3 years ago
Milk containing 3.7% fat and 12.8% total solids is to be evaporated to produce a product containing 7.9% fat. What is the yield
ratelena [41]

Answer:

the yield of product is YP=46.835 % and the concentration of solids is

Cs = 27.33%

Explanation:

Assuming that all the solids and fats remains in the milk after the evaporation, then the mass of product mP will be

Mass of fat in 100 kg of milk = 100 kg* 0.037 = mP* 0.079

mP = 100 kg* 0.037/0.079  =  46.835 kg

then the yield YP of the product is

YP= mP / 100 kg =  46.835 kg / 100 kg = 46.835 %

YP= 46.835 %

the concentration of solids Cs is

Mass of solids in 100 kg of milk = 100 kg* 0.128 = 46.835 kg * Cs

Cs = 100 kg* 0.128 / 46.835 kg  = 0.2733 = 27.33%

Cs = 27.33%

3 0
3 years ago
Please help!!!!
Dafna11 [192]

The intensity of the electric field is 30,000 N/C

Explanation:

The strength of the electric field produced by a single-point charge is given by the equation

E=k\frac{q}{r^2}

where:

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q is the magnitude of the charge

r is the distance from the charge

In this problem, we have:

q=3\cdot 10^{-9}C is the magnitude of the charge

r = 3 cm = 0.03 m is the distance at which we are calculating the field intensity

Substituting, we find:

E=(8.99\cdot 10^9)\frac{3\cdot 10^{-9}}{(0.03)^2}=30,000 N/C

Learn more about electric field:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

5 0
3 years ago
In general, the ________ of a simple machine is the ratio of the distance over which the force is applied to the distance over w
aksik [14]
Mechanical advantage, i hope i helped you!
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3 years ago
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