Answer:
130N
Explanation:
F<em>=</em><em>(</em><em>M1+</em><em>M</em><em>2</em><em>)</em><em>V</em>
<em>F=</em><em> </em><em>(</em><em>7</em><em>0</em><em>+</em><em>6</em><em>0</em><em>)</em><em>*</em><em>1</em>
<em>F=</em><em>1</em><em>3</em><em>0</em><em>*</em><em>1</em>
<em>F=</em><em>1</em><em>3</em><em>0</em><em>N</em><em>/</em><em>/</em>
Answer:
the strength of the magnetic field is 3 x 10⁻⁵ T
Explanation:
Given;
velocity of the cosmic ray, v = 5 x 10⁷ m/s
force experienced by the ray, f = 1.7 x 10⁻¹⁶ N
angle between the ray's velocity and the magnetic field, θ = 45⁰
The strength of the magnetic field is calculated as;

Therefore, the strength of the magnetic field is 3 x 10⁻⁵ T
Since the y axis stayed consistent, we can assume it did not move at all.
(So your answer would be A)