Answer:
1.5 hr
16.7
Explanation:
Zero apparent weight means there's no normal force.
Sum the forces in the centripetal direction.
∑F = ma
mg = mv²/r
v = √(gr)
v = √(7.4×10⁶ m × 10 m/s²)
v = 8602 m/s
The circumference of the equator is:
C = 2πr
C = 2π (7.4×10⁶ m)
C = 4.65×10⁷ m
So the period is:
T = C / v
T = (4.65×10⁷ m) / (8602 m/s)
T = 5405 s
T = 1.5 hr
The initial speed is:
v = C / T
v = (4.65×10⁷ m) / (25 h × 3600 s/h)
v = 517 m/s
The speed increases by a factor of:
8602 m/s / 517 m/s
16.7
8 revolutions every minute
Answer: ∆y = vᵢ∆t + 0.5a(∆t)²
Explanation:
The displacement of an object travelling at a particular acceleration, with an initial velocity vi through a period of ∆t can be expressed using the displacement equation.
d = ut + 0.5at²
Where;
d = y = displacement
u = vᵢ = initial velocity
a = acceleration
t = ∆t = time taken
Therefore,
∆y = vᵢ∆t + 0.5a(∆t)²
The mass of the moon is 7.35×1022Kg. Thus, the value of g on moon is g=1.625
What is luminous intensity: mass of nucleus
Diffraction due to single slit: effects of water pol...
Isobaric process example: 12th important ques...
Hyperopia symptoms: what is mirror formula
The acceleration due to gravity on the surface of the Moon is approximately 1.625 m/s2, about 16.6% that on Earth's surface or 0.166 ɡ. Over the entire surface, the variation in gravitational acceleration is about 0.0253 m/s2 (1.6% of the acceleration due to gravity).