Question

What is the approximate length of the midsegment parallel to BC.

Answer 1

Answer:

Step-by-step explanation:

Alright, lets get started.

There are two points B (-6, 1) and C (5, -1)

The formula for distance between both points is :

$d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

$BC = \sqrt{(5+6)^2+(-1-1)^2}$

$BC = \sqrt{(11)^2+(-2)^2}$

$BC = \sqrt{121+5}$

$BC = \sqrt{125}$

$BC = 11.180$

So, its midsegment will be half of BC.

So midsegment = $\frac{11.180}{2}=5.59$

Hence the answer is 5.6   :    Answer

Hope it will help :)

Answer 2

The answer is C, 5.6 and I hope this is the question you wanted me to answer...