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Dominik [7]
3 years ago
7

What is the approximate length of the midsegment parallel to BC.

Mathematics
2 answers:
denis-greek [22]3 years ago
8 0

Answer:

Step-by-step explanation:

Alright, lets get started.

There are two points B (-6, 1) and C (5, -1)

The formula for distance between both points is :

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

BC = \sqrt{(5+6)^2+(-1-1)^2}

BC = \sqrt{(11)^2+(-2)^2}

BC = \sqrt{121+5}

BC = \sqrt{125}

BC = 11.180

So, its midsegment will be half of BC.

So midsegment = \frac{11.180}{2}=5.59

Hence the answer is 5.6   :    Answer

Hope it will help :)

Pachacha [2.7K]3 years ago
6 0
The answer is C, 5.6 and I hope this is the question you wanted me to answer...
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