Total number of possible outcomes of throwing two dice = 6×6 = 36
Number of outcomes of getting 9 i.e, (3+6),(4+5),(5+4),(6+3) = 4
![P = \frac{Number \: of \: favourable \: outcomes}{ Total \: number \: of \: possible \: outcomes}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7BNumber%20%5C%3A%20of%20%5C%3A%20favourable%20%5C%3A%20outcomes%7D%7B%20Total%20%5C%3A%20number%20%5C%3A%20of%20%5C%3A%20possible%20%5C%3A%20outcomes%7D%20)
7+9=16 you can use that cause that is the opposite equation
![\large \mathfrak{Solution : }](https://tex.z-dn.net/?f=%5Clarge%20%5Cmathfrak%7BSolution%20%3A%20%7D)
Common difference of an Arithmetic progression can be found out by subtracting the preceding term from that given term.
i.e
therefore, the common difference of the above Arithmetic progression is -4 .
Answer:
sorry
Step-by-step explanation: