Using the binomial distribution, it is found that there is a 0.7941 = 79.41% probability that at least one of them is named Joe.
For each student, there are only two possible outcomes, either they are named Joe, or they are not. The probability of a student being named Joe is independent of any other student, hence, the <em>binomial distribution</em> is used to solve this question.
<h3>Binomial probability distribution
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The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- One in ten students are named Joe, hence
.
- There are 15 students in the class, hence
.
The probability that at least one of them is named Joe is:

In which:


Then:

0.7941 = 79.41% probability that at least one of them is named Joe.
To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377
Answer:
Part A: after 9 days the radius of the algae would be 12.81mm so the domain is 9. you would plot the domain at (0,9)
Part B: the y-intercept (the 9) represents the amount of algae the experiment started off with.
Part C: the rate of change is 0.
Step-by-step explanation:
Answer:
$0.51 = 0.51 in decimal form
Step-by-step explanation:
Answer:
x = -18
Step-by-step explanation:
Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other.
Multiply 2 to both sides:
(x/2) * 2 = (-9) * 2
x = -9 * 2
x = -18
x = -18 is your answer.
~
1 persona pagaba 341 por ida y 298 por venido lo que significa que 1 persona paga en total= 639
si son 16 seria= 639*16=10224 en total