Answer:A,D,E
Step-by-step explanation:
Just did the assignment
Answer:
<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>
Step-by-step explanation:
Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:
<h3>To find how many imaginary roots does the polynomial have :</h3>
- Since the degree of given polynomial is 4
- Therefore it must have four roots.
- Already given that the given polynomial has 1 positive real root and 1 negative real root .
- Every polynomial with degree greater than 1 has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>
A = L^2
A = L^2 = 2^2 + 4^2 (Pythagorean’s theorem)
A = L^2 = 20
Therefore the area of the square is 20 units square.
Angle a has a little square box in it, which means right angle, which is equal to 90 degrees.
Angle A = 90 degrees
Angle A m B and the 59 forms a straight line which needs to equal 180
Angle B = 180 - 59 - 90 = 31
Angle B = 31 degrees.
Angle C is a vertical angle with A and B, so Angle C = 90 + 31 = 121 degrees.
Angle D is a vertical angle with 59, so equals 59 degrees.
1.

so

Answers B and D.
2.

Answer D.
3.
The same as point 2. Answer D.
4.
Answer C.