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just olya [345]
3 years ago
9

Help me solve these equations

Mathematics
2 answers:
Rashid [163]3 years ago
7 0
The answer to is is 65
stellarik [79]3 years ago
3 0
The answer to the equation is 65
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How many times the size of 0.81 is 810
MAXImum [283]

Answer:

810 is 100 times the size of 0.81

8 0
3 years ago
A milk carton is 20cm long, 5cm wide and 40cm high. What volume of milk can it hold (in cubic cm)? *​
Marina CMI [18]

Answer:

30 times 10 is 300. 300 times 50 is 15,000.

Step-by-step explanation:

bc i know

6 0
3 years ago
Read 2 more answers
The markup is changed to 34% ;how does the expression for the retail price change?
malfutka [58]
If wholesale cost is x, then retail is x plus the percentage change in x. (1 + .34)x = 1.34x.
8 0
3 years ago
Find the slope of the line that would pass
Leno4ka [110]

Answer:

10

Step-by-step explanation:

Here we go!

Slope Formula:

\frac{ {y}^{2} -  {y}^{1}  }{ {x}^{2} -  {x}^{1} }

What we know: (-4, -52) and (-1, -22)

Plug in the numbers!

\frac{ - 52 - ( - 22)}{ - 4 - ( - 1)}

Fix it!

\frac{ - 52 + 22}{ - 4 + 1}

Add

\frac{ - 30}{ - 3}

Divide

(negative divided by a negative is a positive!!)

Slope is 10

Hope this helps!

4 0
3 years ago
Find the general solution of the following ODE: y' + 1/t y = 3 cos(2t), t > 0.
Margarita [4]

Answer:

y = 3sin2t/2 - 3cos2t/4t + C/t

Step-by-step explanation:

The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt

Comparing the standard form with the given differential equation.

p(t) = 1/t and q(t) = 3cos(2t)

I = e^∫1/tdt

I = e^ln(t)

I = t

The general solution for first a first order DE is expressed as;

y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.

yt = ∫t(3cos2t)dt

yt = 3∫t(cos2t)dt ...... 1

Integrating ∫t(cos2t)dt using integration by part.

Let u = t, dv = cos2tdt

du/dt = 1; du = dt

v = ∫(cos2t)dt

v = sin2t/2

∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt

= tsin2t/2 - cos2t/4 ..... 2

Substituting equation 2 into 1

yt = 3(tsin2t/2 - cos2t/4) + C

Divide through by t

y = 3sin2t/2 - 3cos2t/4t + C/t

Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t

3 0
3 years ago
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