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Vanyuwa [196]
3 years ago
10

Help I will mark u as a brilliant

Mathematics
1 answer:
My name is Ann [436]3 years ago
4 0

Answer:

A

Step-by-step explanation:

A its A i ssssssssseewwwwaaarrrrrr

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Which property of multiplication is shown? (9 + 4)×8=9×8+4×8​
dybincka [34]
Yes I can do that if I can go get my mom is your name or what I can get it
7 0
4 years ago
when the expression: 4x^4 + 24x^3 + 12x^3 + 8x is factored completely, what is the largest factor that can be factored out?
Fofino [41]
Let's start by grouping like terms so we can factor out the most
(4x^4+24x^3)+(12x^2+8x)
now let's factor out as much as possible. we see all coefficients are multiples of 4, we will also factor out as high a degree of x as we can
4x^3(x+6)+4x(3x+2)
now we see that we still have a common multiple of 4x that we can remove
4x(x^2(x+6)+(3x+2))
so we find 4x is the largest value we can factor out
5 0
3 years ago
Read 2 more answers
Construct a circle with a radius of 8cm, and draw an equilateral triangle inside it. Make sure the length of each side measures
Ipatiy [6.2K]

Answer:

<u>Diagram 1</u>

Draw a circle with a radius of 8 cm, ensuring you have clearly marked the center point (black circle with center C1)

Add a point on the circumference of the circle (point C2)

Draw a second circle of radius 8cm with point C2 as its center (red circle with center C2).

<u>Diagram 2</u>

The red circle intersects the black circle at two points (D and E).

Connect these 2 points of intersection with a line segment.

<u>Diagram 3</u>

Draw a third circle with center D and radius DE (shown in blue)

This circle intersects the black circle at point F.

<u>Diagram 4</u>

Draw 2 line segments to connect points D and E with point F - this is your equilateral triangle inside the circle!

8 0
3 years ago
Select the correct answer from each drop-down menu. The base of pyramid A is a rectangle with a length of 10 meters and a width
ASHA 777 [7]

Step-by-step explanation:

The formula of a volume of a pyramid:

V=\dfrac{1}{3}BH

B - base area

H - height

H - height of pyramids

Pyramid A:

B=(10)(2)=200\ m^2

V_A=\dfrac{1}{3}(200)H=\dfrac{200}{3}H\ m^3

Pyramid B:

B=10^2=100\ m^2

V_B=\dfraC{1}{3}(100)H=\dfrac{100}{3}H\ m^3

V_A>V_B\\\\V_A=2V_B

The volume of the pyramid A is twice as large as the volume of the pyramid B.

The new height of pyramid B: 2H

The new volume:

V_{B'}=\dfrac{1}{3}(100)(2H)=\dfrac{200}{3}H\ m^3

The volume of the pyramid A is equal to the volume of the pyramid B.

3 0
3 years ago
Use the formula for perimeter.<br> P=/+w+/+w<br> P=_+_+_+_<br> P=_+_+_<br> P=__+_<br> P=__units
STALIN [3.7K]
1.A(rea)
2.W(idth)
3.W(idth)
4.P(erimeter)
5.A(rea)
6.A(rea)
7.W(idth)
8.A(rea)
The rest is perimeter
7 0
3 years ago
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