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lord [1]
3 years ago
15

A ship is 2.2° off course. If the ship is traveling at 18.0 miles per hour, how far off course will it be after 5 hours?

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
3 0
___x____
\             |
  \           |
     \        |   y
 18  \      |
         \    |
           \ *|---2.2 °

This is a vector problem. The distance of drift is in x (horizontal axis). 
remember that Sin Ф=opposite/hypotenuse. x represents the opposite side form the angle, and 18 is the hypotenuse.
Sin 2.2°=x/18
18 sin 2.2°=x
.691 ≈x

The ship drifts off course .691 miles every hour. .691 x 5 = 5.69 miles after 5 hours.



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The solution to the problem is shown below:
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Area is L x WArea = 9.25 x 10.75Area = 102.125 squard unit


8 0
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ch4aika [34]

Answer:


Step-by-step explanation:

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Thus, by SSS rule, ΔABC ≅ ΔADC

By CPCT, ∠B=∠C

Also, from ΔABD and ΔBCD, we have

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Thus, by SSS rule, ΔABD ≅ ΔBCD

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Draw in diagonals AC and BD. The given information and the shared side AC along with the Reflexive Property can be used to prove ΔABC ≅ ΔADC by the SSS Congruence Postulate. Using CPCTC, ∠B=∠C.The same can be done for ΔABD ≅ ΔBCD using the given information and the shared side BD. This will lead to ∠A=∠C. Therefore, ABCD is a parallelogram because opposite angles are congruent.

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3 years ago
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n200080 [17]

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