Consider the recorded transactions below.E M1. Accounts Recendh...-..._._____. 8.400Service Revenue......-...______. 8.4002. Sup
plies.-........................-....._____..... 2.300Accounts Fame ........................._...... 2.3003. Cash..................................-.......___..... 10.200Accounts Receuable-_.._._____. 10.2004. Advertising Emerse....-...______. 1.000Cash..-.........................-..._.___..... 1.0005. Accounts Pay"--.....-..._._____. 3.700Cash..-.........................-..._.___..... 3.7006. Cash..................................-.......___..... 1.100Deferred m................ 1.100Required:Post each transaction to T-accounts and compute the ending balance of each account. The beginning balance of eachaccount before the transactions is: Cash, $3,400; Accounts Receivable, $4,200; Supplies, 8400; Accounts Payable, $3,500;Deferred Revenue, 5300. Service Revenue and Advertising Expense each have a beginning balance of zero.
1 answer:
Answer:
answer is present in the attachment
Step-by-step explanation:
you have misquoted the amounts for the opening balances of Supplies and Deferred Revenue. I checked the internet for the right amounts and those are $400 for Supplies and $300 for Deferred Revenue. I have attached a picture to answer your question. Please find the attachment with the name "Answer".
However, I have also solved the question with the amounts that you provided and have attached a picture for it with the name "Answer 2".
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Answer:
The slope of the line between these two points is 1.50.
Step-by-step explanation:
The general form of the regression line is:
Here,
<em>y</em> = dependent variable
<em>x</em> = independent variable
<em>m</em> = slope
<em>c</em> = intercept.
The formula to compute slope using two-point method is:
In this case the dependent variable is the cost per week to feed and independent variable is the weight of the hamster.
The two points are:
(<em>x</em>₁, <em>y</em>₁) = (3, 3.50)
(<em>x</em>₂, <em>y</em>₂) = (4.8, 6.20)
Compute the slope as follows:
Thus, the slope of the line between these two points is 1.50.
The quadrants are as follows:
The 1st quadrant has the points which have both x and y positive and the 3rd quadrant has the points which have both x and y negative. If the ordered pair and the same x and y value, if ons is positive, the other also is, and the same for negative.
So, at first we see that there are point where the x and y are the same and that are in the 1st or 3rd quadrant.
However, there is one special case:
When x and y are 0, that is, the ordered pair is (0, 0).
Since this point is the origin, it doesn't lie on any of the quadrants.
Thus, this affirmative is sometimes true. Every point but (0, 0) that have same x and y values are in the 1st or 3rd quadrant except for (0, 0).
