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Nitella [24]
4 years ago
14

A school wishes to form three sides of a rectngular playground using 480 meters of fencing. The playground borders the school bu

ilding, so the fourth side does not need fencing.
Mathematics
2 answers:
nirvana33 [79]4 years ago
5 0

Answer

school building, so the fourth side does not need Fencing. As shown below, one of the sides has length J.‘ (in meters}. Side along school building E (a) Find a function that gives the area A (I) of the playground {in square meters) in

terms or'x. 2 24(15): 320; - 2.x (b) What side length I gives the maximum area that the playground can have? Side length x : [1] meters (c) What is the maximum area that the playground can have? Maximum area: I: square meters

Step-by-step explanation:

UkoKoshka [18]4 years ago
4 0

Answer:

Step-by-step explanation:

If you were talking about how many meters of fencing the school would need it would be 160 meters. The reason i say this is because if you were to divide the 3 sides of the playground by 48o meters of fencing you would get 160 meters of fencing. If this is not the answer your looking for than please state the question next time. THANK YOU

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We can’t understand how to find the pattern
cupoosta [38]

Answer:

Pattern: subtract 2 from the input to get the output

When the input is 9, the output is 7

When the input is 13, the output is 11

Step-by-step explanation:

» <u>Application + Solution</u>

To find the pattern, we have to look for common things we notice between the input and output.

  • After analyzing, we can surely notice that we subtract two from the input each time to get the output because 3 - 2 = 1, 8 - 2 = 6, 15 - 2 = 13, and 20 - 2 = 18.

Now that we realized the pattern, we subtract 2 from 9 and 13.

  • 9 - 2 = 7
  • 13 - 2 = 11
5 0
2 years ago
A magician has a collection of 52 cards, with 26 red and 26 black cards. Four of these cards are classified as 'special', and tw
Brums [2.3K]

Answer:

option B (28/52)

Step-by-step explanation:

from probability

P(A∪B)=P(A)+P(B)-P(A∩B)

where

P(A∪B) = probability that event A or B happen

P(A∩B) = probability that event A and B happen simultaneously

P(A) =  probability that event A happen

P(B) =  probability that event B happen

the probability that the card is special or red

P( special or red)= P(special) + P(red) - P( special and red)

since

P(special)= 4/52

P(red) = 26/52

P( special and red) = 2/52

therefore

P( special or red)= 4/52 + 26/52 -  2/52 = 28/52

P( special or red)= 28/52

(option B)

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4 years ago
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