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Nitella [24]
4 years ago
14

A school wishes to form three sides of a rectngular playground using 480 meters of fencing. The playground borders the school bu

ilding, so the fourth side does not need fencing.
Mathematics
2 answers:
nirvana33 [79]4 years ago
5 0

Answer

school building, so the fourth side does not need Fencing. As shown below, one of the sides has length J.‘ (in meters}. Side along school building E (a) Find a function that gives the area A (I) of the playground {in square meters) in

terms or'x. 2 24(15): 320; - 2.x (b) What side length I gives the maximum area that the playground can have? Side length x : [1] meters (c) What is the maximum area that the playground can have? Maximum area: I: square meters

Step-by-step explanation:

UkoKoshka [18]4 years ago
4 0

Answer:

Step-by-step explanation:

If you were talking about how many meters of fencing the school would need it would be 160 meters. The reason i say this is because if you were to divide the 3 sides of the playground by 48o meters of fencing you would get 160 meters of fencing. If this is not the answer your looking for than please state the question next time. THANK YOU

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1 year ago
I need help pleace ​
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Answer

<em>length = width + 15</em>

<em>Area = length * width; area is 54 square feet.</em>

<em>Two equations are:</em>

<em>L = W + 15</em>

<em>L * W = 54</em>

<em>To solve, we substitute first equation into second equation:</em>

<em>(W + 15) * W = 54</em>

<em>w^2 + 15w = 54</em>

<em>w^2 + 15w - 54 = 0</em>

<em>(w+18)(w-3) = 0</em>

<em>w = -18 or 3</em>

<em>The width cannot be negative, so 3 is the width and since length is 15 more than width, length is 18:</em>

<em />

<em>Length = 18 feet</em>

<em>Width = 3 feet</em>

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Step-by-step explanation:

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