Question

What is the solution of the equation over the complex numbers?

Answer 1

Answer:

The solutions of the equation over the complex numbers are $x=2i\sqrt{5},-2i\sqrt 5$

Step-by-step explanation:

Given : Equation $x^2+20=0$

To find : What is the solution of the equation over the complex numbers?

Solution :

Equation $x^2+20=0$

Solve the equation,

Subtract 20 both side,

$x^2=-20$

Taking square root both side,

$x=\pm\sqrt{-20}$

$x=\pm\sqrt{-2\times 2\times 5}$

$x=\pm 2i\sqrt{5}$

$x=2i\sqrt{5},-2i\sqrt 5$

Therefore, The solutions of the equation over the complex numbers are $x=2i\sqrt{5},-2i\sqrt 5$

Answer 2

2x = -20
x = -20 / 2
x = -10 
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