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stira [4]
3 years ago
13

Divide if possible

14}{7} " alt=" \frac{ - 14}{7} " align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
Mamont248 [21]3 years ago
7 0
-14 divided by 7 is -2
lisov135 [29]3 years ago
6 0
Divide -14 by 7 your answer is -2
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A certain television is advertised as a 26 inch TV (the diagonal length). If the width of the TV is 10 inches, how many inches t
emmainna [20.7K]

Answer: The TV is 24 inches tall

Step-by-step explanation: The question has provided the diagonal and the width of the rectangle shaped television. From this bit of information, we can deduce that the diagonal of the rectangle (television) is also the Hypotenuse (26 inches) while the the other two sides are the Length and the Width (10 inches).

For every right angled triangle, we can apply the Pythagoras theorem to solve for any unknown side. The theorem states that

AC² = BC² + AB²

Where AC is the hypotenuse (longest side)

26² = 10² + AB²

676 = 100 + AB²

Subtract 100 from both sides of the equation

576 = AB²

Add the square root sign to both sides of the equation

√576 = √AB²

24 = AB

Therefore, the height of the television is 24 inches

7 0
4 years ago
the larger of two numbers is 1 less than 3 times the smaller number. if twice the smaller is increased by the larger number, the
Y_Kistochka [10]

x = 3y - 1

2y + x = x + 18


2y + 3y - 1 = 3y - 1 + 18

5y - 1 = 3y + 17

2y = 18

y = 9


x = 3(9) - 1

x = 27 - 1

x = 26

5 0
3 years ago
What situation should be used to rewrite 16(x^3+1)^2 -22(x^3+1)-3=0 as a quadratic equation
Oliga [24]
16(x^3+1)^2-22(x^3+1)-3=0

Use substitution:  x^3+1=t

16t^2-22t-3=0\\\\16t^2-24t+2t-3=0\\\\8t(2t-3)+1(2t-3)=0\\\\(2t-3)(8t+1)=0\iff2t-3=0\ \vee\ 8t+1=0

2t-3=0\ \ \ |+3\\\\2t=3\ \ \ |:2\\\\t=\dfrac{3}{2}\\..............................\\8t+1=0\ \ \ \ |-1\\\\8t=-1\ \ \ \ |:8\\\\t=-\dfrac{1}{8}

we're going back to substitution:

x^3+1=\dfrac{3}{2}\ \vee\ x^3+1=-\dfrac{1}{8}\ \ \ \ |subtract\ 1\ from\ both\ sides\ of\ the\ equations\\\\x^3=\dfrac{1}{2}\ \vee\ x^3=-\dfrac{9}{8}\\\\x=\sqrt[3]{\dfrac{1}{2}}\ \vee\ x=\sqrt[3]{-\dfrac{9}{8}}


x=\dfrac{1}{\sqrt[3]2}\ \vee\ x=-\dfrac{\sqrt[3]9}{2}\\\\\boxed{x=\dfrac{\sqrt[3]4}{2}\ \vee\ x=-\dfrac{\sqrt[3]9}{2}}

4 0
3 years ago
Please do a fraction in simplest form.
777dan777 [17]

Answer:

25 would be the answer

3 0
3 years ago
Read 2 more answers
What is absolute value and why is it always positive?
xxMikexx [17]

Answer:

Step-by-step explanation:

An absolute value is the distance a number is from 0 on the number line. So, regardless if it is a negative or a positive number, the distance from that number to 0 will always be positive. For example, -5 is 5 units away from 0, and 5 is also 5 units from zero. They have the same absolute value, even though one is negative and the other is positive.

6 0
3 years ago
Read 2 more answers
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