All categories

3 years ago

Find a set of four integers such that their order and the order of their absolute values are the same.

1 answer:

8 0

If you pick only positive numbers, the absolute value will have no effect, and the original set and the set of the absolute value will be exactly the same:

$A = \{1,2,3,4,5\}$

is still

$A = \{|1|,|2|,|3|,|4|,|5|\} = \{1,2,3,4,5\}$

You might be interested in

Can someone tell me the answer to both of these

omeli [17]

Answer:

First question --> C) 8.5h

Second question --> D) 2

Step-by-step explanation:

First question

Terry earns $10 per hour

Jill earns 20% less which is $2 less

Jill earns $8 per hour

Jerry earns $0.50 more per hour than Jill

Jerry earns $8.50 per hour

Second question

x = 2

y = 4

(2x + 3y) / 4 - 2 = ?

Use PEMDAS

so Parentheses first, then divide, then subtract

So.... (2x + 3y) = (2*2 + 3*4) = (4 + 12) = 16

Then divide

16/4 = 4

Then subtract

4 - 2 = 2

3 0

3 years ago

Read 2 more answers

A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of

Ivenika [448]

The equation for the height of the rocket at time t given

$h= -16t^2+192t$

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

$h= -16t^2+192t$

$560 = -16t^2+192t$

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

$560 = -16(t^2 - 12t)$

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

$560/-16 = -16(t^2-12t)/-16$

$-35 = t^2 -12t$

Now we will move -35 to the righ side by adding 35 to both sides.

$-35+35 = t^2-12t+35$

$0 = t^2 -12t+35$

$t^2-12t+35 = 0$

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

$t^2-12t+35 =0$

$(t-5)(t-7) =0$

So by using zero product property we will get

$t-5 =0$

$t-5+5 = 0+5$

$t=5$

Also $t-7 =0$

$t-7+7 = 0+7$

$t=7$

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

$h= -16t^2+192t$

$0= -16t^2 + 192 t$

$0 = -16(t^2-12t)$

$-16(t^2-12t) = 0$

We will move -16 to the other side by dividing it to both sides.

$-16(t^2-12t)/-16 = 0/-16$

$t^2-12t = 0$

We will take out the common factor t from the left side. By taking out t we will get,

$t(t-12) = 0$

We will use zero product property now. By using that we will get,

$t = 0$

ans also $t-12 = 0$

$t-12+12 = 0+12$

$t = 12$

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0

3 years ago

Can someone plss help me with this!!!

qaws [65]

Answer

Algae to(-->) Mayfly nymph, Mayfly nymph to Dragonfly nymph and Trout, Dragonfly nymph also to Trout, Trout to Osprey.

please give me brainliest.

8 0

2 years ago

Look at picture for problem

Jobisdone [24]

Add 2 3/4 and 2 1/2 and you’ll get ur answer. area means total and when u see area, it means add

8 0

2 years ago

Which two expressions are equivalent?

Elena L [17]

Answer:

C) 4a-2a=a+a

Step-by-step explanation:

4a-2a=2a

2a=a+a

2a=2a

3 0

3 years ago