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3 years ago

Find a set of four integers such that their order and the order of their absolute values are the same.

1 answer:

8 0

If you pick only positive numbers, the absolute value will have no effect, and the original set and the set of the absolute value will be exactly the same:

$A = \{1,2,3,4,5\}$

is still

$A = \{|1|,|2|,|3|,|4|,|5|\} = \{1,2,3,4,5\}$

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U'LL GET BRAINLIEST IF U ANSWER FIRST

Tanzania [10]

Answer:

$\boxed{\bold{a+2b}}$

Explanation:

<u>Simplify expression to find its equivalent</u>

<u></u>

Expand $\bold{2\left(a+2b\right): \ 2a+4b}$

= $\bold{2a+4b-a-2b}$

Simplify $\bold{2a+4b-a-2b: \ a+2b}$

= $\bold{a+2b}$

Mordancy.

6 0

3 years ago

16. A telemarketer makes six phone calls per hour and is able to make a sale on 30% of these contacts. During the next two hours

Reika [66]

Answer:

a) 23.11% probability of making exactly four sales.

b) 1.38% probability of making no sales.

c) 16.78% probability of making exactly two sales.

d) The mean number of sales in the two-hour period is 3.6.

Step-by-step explanation:

For each phone call, there are only two possible outcomes. Either a sale is made, or it is not. The probability of a sale being made in a call is independent from other calls. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A telemarketer makes six phone calls per hour and is able to make a sale on 30% of these contacts. During the next two hours, find:

Six calls per hour, 2 hours. So

$n = 2*6 = 12$

Sale on 30% of these calls, so $p = 0.3$

a. The probability of making exactly four sales.

This is P(X = 4).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{12,4}.(0.3)^{4}.(0.7)^{8} = 0.2311$

23.11% probability of making exactly four sales.

b. The probability of making no sales.

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.3)^{0}.(0.7)^{12} = 0.0138$

1.38% probability of making no sales.

c. The probability of making exactly two sales.

This is P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{12,2}.(0.3)^{2}.(0.7)^{10} = 0.1678$

16.78% probability of making exactly two sales.

d. The mean number of sales in the two-hour period.

The mean of the binomia distribution is

$E(X) = np$

$E(X) = 12*0.3 = 3.6$

The mean number of sales in the two-hour period is 3.6.

4 0

3 years ago

1/6d + 2/3 = 1/4(d-2) how to solve

natita [175]

Greetings!

Solve for d.
$1/6d + 2/3 = 1/4(d-2)$
Distribute the Parenthesis.
$1/6d + 2/3 = 1/4*d+1/4*-2$
$1/6d + 2/3 = 1/4d+1/4*-2/1$
$1/6d + 2/3 = 1/4d-2/4$
Reduce.
$1/6d + 2/3 = 1/4d-1/2$
Add -2/3 to both sides.
$(1/6d + 2/3)+(-2/3)=(1/4d-1/2)+(-2/3)$
Simplify.
$1/6d=1/4d-3/6-4/6$
$1/6d=1/4d-7/6$
Add -1/4d to both sides.
$(1/6d)+(-1/4d)=(1/4d-7/6)+(-1/4d)$
Simplify.
$2/12d)-3/12d=-7/6$
$-1/12d=-7/6$
Divide both sides by -1/12.
$(-1/12d)/-1/12=(-7/6)/-1/12$
Simplify.
$d=(-7/6)*-12/1$
$d=84/6$
Reduce.
$d=14/1$
$d=14$

Hope this helps.
-Benjamin

7 0

3 years ago

Which pair of numbers has a GCF of 3? Group of answer choices (A) 3 and 18 (B) 8 and 24 (C)12 and 18 (D) 1 and 3

Arte-miy333 [17]

Answer:

A, B and C

Step-by-step explanation:

A) 3 and 18 = has 3 as factor

B) 8 and 24 = has 3 as factor

C) 12 and 18 = has 3 as factor

D) 1 and 3 = has as factor of 1 and 3

so the answer is A, B and C

5 0

3 years ago

An equivalent expression for 12x+1 and 2(2x+5) please help

zhannawk [14.2K]

<h2>Answer:</h2>

8x+9

<h2>Step-by-step explanation:</h2>

12x+1 = 2(2x+5)

<h3><em><u>Handle the brackets first</u></em></h3>

12x+1 = 4x+10

<h3><em><u>Collect like terms</u></em></h3>

=8x+9

3 0

3 years ago