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Xelga [282]
3 years ago
6

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule. A (n)=1+(n-1)(-4.1)

Mathematics
1 answer:
djverab [1.8K]3 years ago
8 0
A(1) = 1 + (1-1)(-4.1) = 1

A(1) = 1 + (4-1)(-4.1) = -11.3

A(1) = 1 + (10-1)(-4.1) = -35.9

Answer is D



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vampirchik [111]
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Employ a standard trick used in proving the chain rule:

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For the leftmost limit, we make a substitution y=\sqrt x. Now, if we make a slight change to x by adding a small number h, this propagates a similar small change in y that we'll call h', so that we can set y+h'=\sqrt{x+h}. Then as h\to0, we see that it's also the case that h'\to0 (since we fix y=\sqrt x). So we can write the remaining limit as

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So we find that

\dfrac{\mathrm d\tan\sqrt x}{\mathrm dx}=\dfrac{\sec^2\sqrt x}{2\sqrt x}
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