B) In the process of the citric cycle that occurs in the mitochondrial matrix, electrons from this chemical pathways move from one protein complex to another and are ultimately accepted by oxygen molecule in the formation a water molecule. Concomitantly, protons are transported to the intermembrane space. Accumulation of H+ ions in the mitochondrial membrane creates an electromotive force that is harnessed by ATP synthase to enable the phosphorylation of an ADP to ATP.
A) A leaky membrane, therefore, would interfere with the accumulation of protons in the intermembrane space. This will reduce the electromotive force that is harness by the ATP synthase to produce ATP by phosphorylation of ADP. Consequently, this defective mitochondria will produce less ATPs than a healthy mitochondria.
Answer:
A
Explanation:
Based on the word choice and structure of the sentence, A gives off the most positive connotation upon reading out of all of your choices.
Hope this helps!
Answer:
Pangenesis
Explanation:
The theory of 'pangenesis' was proposed by Darwin to explain the process of inheritance of genetic traits from one generation to next. According to this theory, gemmules are the tiny particles produced by all the somatic cells of the body of living beings. These gemmules are also called pangene. Blood carries gemmules from all the body cells to the gonads. These gemmules from all the somatic cells form germ cells in gonads.
<span>Human immunodeficiency virus or better known as HIV disables the immune system </span>
Answer:
3/16
Explanation:
This question involves two different genes coding for earlobe shape and earwax quality. The alleles for attached earlobes (A) and wet earwax (E) are dominant over the alleles for free earlobes (a) and dry earwax (e).
According to this question, two humans mate who are heterozygous for both genes i.e. AaEe × AeEe. Each parent will produce the following gametes: AE, Ae, aE, ae.
Using these gametes in a punnet square (see attached image), the following proportion of offsprings will be produced:
* Attached earlobe, wet earwax (A_E_) = 9/16
* Attached earlobe, dry earwax (A_ee) = 3/16
* Free earlobe, wet earwax (aaE_) = 3/16
* Free earlobe, dry earwax (aaee) = 1/16
Hence, the probability of these parents having their first child with dry earwax (ee) and attached earlobes (A_) i.e. genotype A_ee is 3/16.
