3 years ago

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Mathematics

1 answer:

aleksklad [387]3 years ago

6 0

Answer:

the domain is all realz

the range is all realz

Step-by-step explanation:

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The area of circle K when c=24x^2 pi

Gala2k [10]

Answer: $\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi },\:x=-\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi }$

Step-by-step explanation:

$c=24x^2 pi$

Switch sides:

$24x^2\pi =Kc$

divide both sides by $24\pi$

$\frac{24x^2\pi }{24\pi }=\frac{Kc}{24\pi }$

simplify:

$x^2=\frac{Kc}{24\pi }$

$x^2=\frac{Kc}{24\pi }$ $x=\sqrt{\frac{Kc}{24\pi }},\:x=-\sqrt{\frac{Kc}{24\pi }}$

answer: $x=\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi },\:x=-\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi }$

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3 years ago

How do I solve this equation?

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