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Inessa [10]
3 years ago
11

Yo I need help.........

Mathematics
1 answer:
Artist 52 [7]3 years ago
3 0
23/36 is the next answer I believe. Someone correct me if I’m wrong
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Determine the type and number of solutions of 7x^2+3x+8=0
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7x^2+3x+8=0 \\ \\a =7, \ b=3 ,\ c=8 \\ \\\Delta =b^2 - 4ac = 3^2 -4\cdot 7\cdot 8=9-224=-215\\ \\ Answer : \ \Delta \ is \ negative,\ this \ gives \ two \ imaginary \ solutions


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It would take her 10 track practices to get up to 40 miles.

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4 years ago
PLEASE HELP. !!!!!!!!!!
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the last one bottom right

Step-by-step explanation:

well, did it in my head, but the idea is to calculate it out

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g The total national health expenditures per capita (in dollars) for 2006 and projected to 2021 can be modeled with the equation
Alex73 [517]

Answer:

a) The predicted per capita health expenditures for 2018 is $11943.5.

b) After 2018, it will take 16 years for the 2018 expenditures to double

Step-by-step explanation:

The total national health expenditures per capita, in dollars, is given by the following equation:

H(t) = 6791e^{0.04343t}

In which t is the number of years after 2005.

a. Find the predicted per capita health expenditures for 2018.

2018 is 13 years after 2005, so this is H(13).

H(t) = 6791e^{0.04343t}

H(13) = 6791e^{0.04343*13}

H(13) = 11943.5

The predicted per capita health expenditures for 2018 is $11943.5.

b. According to the model, how long will it take the 2018 expenditures to double?

First we find how many years after 2005, in which t is found when H(t) = 2*11943.5.

So

H(t) = 6791e^{0.04343t}

2*11943.5 = 6791e^{0.04343t}

e^{0.04343t} = \frac{2*11943.5}{6791}

e^{0.04343t} = 3.5174

Applying ln to both sides

\ln{e^{0.04343t}} = \ln{3.5174}

0.04343t = \ln{3.5174}

t = \frac{\ln{3.5174}}{0.04343}

t = 29

It will take 29 years after 2005 = 29-13 = 16 years after 2018.

After 2018, it will take 16 years for the 2018 expenditures to double

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______are loans to a company or government for a set amount of time they earn interest in are considered low-risk Investments
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