1. how many times 47 fits on 985? 20×47=940
try higher: 47×21=987. So use 20. subtract 985-940=45. how many times does 47 fit on 45? 0 so the answer should be 20 remainder 45
Answer:
Step-by-step explanation:
Hi there!
Since the scale is 1 in = 4 ft, we divide both the length and width by 4 to get the new length and width with the scale factor applied.
16 / 4 = 4
12 / 4 = 3
So, the
length = 4
width = 3
Hope this helps!
Answer:
200 ft.
2 jumps
Step-by-step explanation:
The slide is placed at coordinates (-2,0) and the fountain is placed at coordinates (-2,-2).
(A) Therefore, using the distance between two known points formula, the distance from the slide to the fountain is given by
units.
Now, given that each unit on the grid represents 100 ft.
So, the distance from slide to the fountain is (100 × 2) = 200 ft. (Answer)
(B) Now, if each jump = 100 ft, then the slide is 2 jumps apart from the fountain. (Answer)
We know the distance between two known points on the coordinate plane (
) and (
) is given by the following formula
Distance = 
Subsitute
2a-16=b=a+2
2a-16=a+2
subtract a from boths ides
a-16=2
add 16
a=18